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如何在 URL 中获取 Id 以显示 Symfony 5 的评论?

[英]How do I get Id in the URL to display comments with Symfony 5?

I'm coding a blog with Symfony 5 and I have issues getting the Id from the URL to display comments from my Database.我正在使用 Symfony 5 编写博客,但在从 URL 获取 Id 以显示来自我的数据库的评论时遇到问题。

To sum up: - I have a view "/fiche/{id}" wish displays specific game informations.总结一下: - 我有一个视图“/fiche/{id}”希望显示特定的游戏信息。 - People can leave a comment below, the comment goes in Database with a foreign Key named "jeu_id" wish is the game where the comment were posted. - 人们可以在下面发表评论,评论进入数据库,带有名为“jeu_id”的外键希望是发布评论的游戏。

  • The goal is to display now all the comments wish were posted on this specific game.目标是现在显示所有希望在此特定游戏上发布的评论。 I want to display all the comments with foreign key "jeu_id" wish is in the url "/fiche/{id}".我想显示所有带有外键“jeu_id”的评论希望在 url“/fiche/{id}”中。

Here's the method in my controller:这是我的 controller 中的方法:

     /**
     * @Route("/fiche/{id}", name="fiche", methods={"POST", "GET"})
     */
    public function fiche($id, Jeux $jeux, Request $request): Response
    {
        $id = (int)$request->get('id');
        $commentaires = $this->getDoctrine()->getRepository(Jeux::class)->find($id);

        $commentaire = new Commentaires();
        $commentaire->setCreatedAt(new \DateTime("NOW"));
        $request = Request::createFromGlobals();
        $commentaire->setJeu($jeux);
        $form = $this->createForm(CommentairesType::class, $commentaire);
        $form->handleRequest($request);

        //test variable
        //dd($id);
        dd($commentaire->getJeu($id));

        if ($form->isSubmitted() && $form->isValid()) {
            $entityManager = $this->getDoctrine()->getManager();
            $entityManager->persist($commentaire);
            $entityManager->flush();

            return $this->redirectToRoute('liste');
        }
        return $this->render('main/fiche.html.twig', [
            'commentaires' => $commentaires,
            'jeux' => $jeux,
            'form' => $form->createView(),
        ]);
    }

Here's the concern variables in entity "Commentaires":这是实体“评论家”中的关注变量:

    /**
     * @ORM\ManyToOne(targetEntity=Jeux::class, inversedBy="commentaires")
     * @JoinColumn(name="jeu_id", referencedColumnName="id")
     * @ORM\JoinColumn(nullable=true)
     */
    private $jeu;

    public function getJeu(): ?Jeux
    {
        return $this->jeu;
    }

    public function setJeu($jeu): self
    {
        $this->jeu = $jeu;

        return $this;
    }

Here's the concern variables in entity "Jeux":这是实体“Jeux”中的关注变量:

    /**
     * @ORM\OneToMany(targetEntity=Commentaires::class, mappedBy="jeu", orphanRemoval=true)
     */
    private $commentaires;

    /**
     * @return Collection|Commentaires[]
     */
    public function getCommentaires(): Collection
    {
        return $this->commentaires;
    }

I think the right way would be something like this:我认为正确的方法是这样的:

/**
 * @Route("/fiche/{jeux}", 
 * name="fiche"
 */
public function fiche(Request $request, Jeux $jeux, EntityManagerInterface $em): Response
{
    $form = $this->createForm(CommentaireType::class);
    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        $commentaire = $form->getData();
        $commentaire->setCreatedAt(new \DateTime("NOW"));
        $jeux->addCommentaire($commentaire);

        $em->persist($commentaire);
        $em->flush();

        return $this->redirectToRoute('liste');
    }

    return $this->render('main/fiche.html.twig', [
        'commentaires' => $jeux->getCommentaires(),
        'jeux' => $jeux,
        'form' => $form->createView(),
    ]);
}

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