如何从两个列表中获取一个列表

Question

I have two lists (both are already ordered correctly and contain 180.000 items each). The first one contains the filenames.

filenames[0]
s01_l01/1000_1.png

The second list contains the labels of the files.

labels[0]
'1BK 7475'

How do I now get a list, which looks like this: [[filename_1, label_1], [filename_2, label_2],..., [filename_n, label_n]]?

list_of_filenames_labels[0]
[s01_l01/1000_1.png, '1BK 7475']

Thanks a lot!

Answer 1

You can do that with a simple map with lambda function

a = ['1','2','3']
b = ['a','b','c']
c = list(map(lambda x, y: [x,y], a, b))

The output for c would be

c = [['1', 'a'], ['2', 'b'], ['3', 'c']]

Answer 2

The output you specified is similar to the output of zip , except that it is a list of lists rather than a list of tuples. This would convert them to lists:

[list(t) for t in zip(filenames, labels)]

Answer 3

Here:

list_of_filenames_labels = [[filename,label] for filename,label in zip(filenames,labels)]

Answer 4

if both list have same length, you can use enumerate function

list_of_filenames_labels = [[filename, labels[i]] for i, filename in enumerate(filenames)]