[英]how to convert wrong format of string into JSONObject
I am getting wrong format of json
string from response.我从响应中得到了错误的json
字符串格式。 Now I need to correct it.现在我需要纠正它。 But I am not able to do.但我做不到。 Below is the response I am getting from some mongodb
related API:以下是我从一些与mongodb
相关的 API 得到的响应:
{
"_id" : ObjectId("5ecd66aa9fd30b21cac18beb"),
"_class" : "com.wpits.mongo.docs.UssdMongoLog",
"jsonObject" : {
"message" : "MessageBase{CommandLength=148, CommandID=BasicContinue, CommandStatus=0, SenderCB=-516163402, ReceiverCB=1896231456, AccountName=atg189, Password=AtG189, SystemType=, InterfaceVersion=23, UssdVersion=PHASEIII, UssdOpType=Request, MsIsdn=211919002392, ServiceCode=152, CodeScheme=sevenDigit, UssdString=Reply with Song Id to Subscribe.\n870. Nixx Corona IVR English 02\n295. Nixx Tone\n\n #. Main Menu, SwitchMode=0, ChargeRatio=0, ChargeType=0, ChargeSource=null, ChargeLocation=0, Message=null}",
"timestamp" : "2020-05-26 09:58:398"
}
}
Now, as it can be seen key message
has a value which is not a correct JSON
format.现在,可以看出关键message
的值不是正确的JSON
格式。 I wanted this to be like below:我希望它如下所示:
"message" : "MessageBase" : {"CommandLength"="148", "CommandID"="BasicContinue", "CommandStatus"="0", "SenderCB"="-516163402", "ReceiverCB"="1896231456", "AccountName"="atg189", "Password"="AtG189", "SystemType"="", "InterfaceVersion"="23", "UssdVersion"="PHASEIII", "UssdOpType"="Request",....}
I am using org.json.simple.JSONObject
and org.json.simple.JSONParser
like below:我正在使用org.json.simple.JSONObject
和org.json.simple.JSONParser
如下所示:
public static void main(String[] args) {
try {
JSONObject obj = new JSONObject();
obj.put("message", "MessageBase{CommandLength=148, CommandID=BasicContinue, CommandStatus=0, SenderCB=-516163402, ReceiverCB=1896231456, AccountName=atg189, Password=AtG189, SystemType=, InterfaceVersion=23, UssdVersion=PHASEIII, UssdOpType=Request, MsIsdn=211919002392, ServiceCode=152, CodeScheme=sevenDigit, UssdString=Reply with Song Id to Subscribe.\n870. Nixx Corona IVR English 02\n295. Nixx Tone\n\n #. Main Menu, SwitchMode=0, ChargeRatio=0, ChargeType=0, ChargeSource=null, ChargeLocation=0, Message=null}");
String msg = (String)obj.get("message");
msg = msg.replace("MessageBase", "\"MessageBase\" : ");
JSONParser parser = new JSONParser();
JSONObject obj2 = (JSONObject)parser.parse(msg);
System.out.println(obj2.toJSONString());
}catch(Exception ex) {
ex.printStackTrace();
}
}
But not able to do that... is there any utility class that I can use in order to correct this format?但无法做到这一点......我可以使用任何实用程序 class 来纠正这种格式吗?
edit编辑
based on @libanbn suggestion I tried with following program:根据@libanbn 的建议,我尝试了以下程序:
public static void main(String[] args) {
try {
JSONObject obj = new JSONObject();
obj.put("message", "MessageBase{CommandLength=148, CommandID=BasicContinue, CommandStatus=0, SenderCB=-516163402, ReceiverCB=1896231456, AccountName=atg189, Password=AtG189, SystemType=, InterfaceVersion=23, UssdVersion=PHASEIII, UssdOpType=Request, MsIsdn=211919002392, ServiceCode=152, CodeScheme=sevenDigit, UssdString=Reply with Song Id to Subscribe.\n870. Nixx Corona IVR English 02\n295. Nixx Tone\n\n #. Main Menu, SwitchMode=0, ChargeRatio=0, ChargeType=0, ChargeSource=null, ChargeLocation=0, Message=null}");
String msg = (String)obj.get("message");
msg = msg.replace("MessageBase", "");
msg = msg.replace("\n", "");
msg = msg.replace("{", "{\"");
msg = msg.replace("}", "\"}");
msg = msg.replace("=", "\"=\"");
msg = msg.replace(",", "\",\"");
msg = "{\"message\" : "+msg+"}";
msg = msg.replace("=", ":");
System.out.println(msg);
JSONParser parser = new JSONParser();
JSONObject obj2 = (JSONObject)parser.parse(msg);
System.out.println(obj2.toJSONString());
}catch(Exception ex) {
ex.printStackTrace();
}
}
it solved my problem..它解决了我的问题..
You can see that the string follows a pattern of MessageBase{key=value, key=value, ...}
.您可以看到字符串遵循MessageBase{key=value, key=value, ...}
的模式。
Before you try to convert the string to JSON object, you must change the format.在尝试将字符串转换为 JSON object 之前,您必须更改格式。 Since the string follows a consistent pattern, you can use regular expressions to reformat it before parsing to JSON.由于字符串遵循一致的模式,您可以在解析为 JSON 之前使用正则表达式重新格式化它。
You could try this.. The idea is to build a valid json from your string.你可以试试这个。这个想法是从你的字符串中构建一个有效的 json 。
public static void main(String[] args) {
try {
JSONObject obj = new JSONObject();
String msg = (String) obj.get("message");
msg = "MessageBase{CommandLength=148, CommandID=BasicContinue, CommandStatus=0, SenderCB=-516163402, ReceiverCB=1896231456, AccountName=atg189, Password=AtG189, SystemType=, InterfaceVersion=23, UssdVersion=PHASEIII, UssdOpType=Request, MsIsdn=211919002392, ServiceCode=152, CodeScheme=sevenDigit, UssdString=Reply with Song Id to Subscribe.\n870. Nixx Corona IVR English 02\n295. Nixx Tone\n\n #. Main Menu, SwitchMode=0, ChargeRatio=0, ChargeType=0, ChargeSource=null, ChargeLocation=0, Message=null}";
msg = msg.replace("MessageBase{", "{\"MessageBase\" : \"");
msg = msg.substring(0, msg.length()-1).concat("\"}");
JSONParser parser = new JSONParser();
JSONObject obj2 = (JSONObject) parser.parse(msg);
System.out.println(obj2.toJSONString());
} catch (Exception ex) {
ex.printStackTrace();
}
}
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