我如何将一个列表的元素拆分为另一个列表的元素，但按照它们在列表中的显示顺序

Question

something like this:

equation=list_1[0]+list_2[0]+list_1[1]+list_2[1]+list_1[2]+list_2[2]+list_1[3]

but how can I make it more general? this will only work if i know the number of elements in each list.

Answer 1

Loop over the result of zip(list_1, list_2) :

equation = ""
for i1, i2 in zip(list_1, list_2):
    equation += str(i1) + str(i2)

If ths lists have different lengths, you can append the extra elements afterward:

if len(list_1) > len(list_2):
    equation += sum([str(i) for i in list_1[len(list_2):]])
elif len(list_2) > len(list_1):
    equation += sum([str(i) for i in list_2[len(list_1):]])