如何使用 RegExp 过滤 object 并返回新的 object

Question

I have an object:

object1 = {
dEabc: 1,
dEasdf: 2,
dEjfhs: 5,
bhsn: 7,
oki: 9
}

My goal is to get a new object which contains only the keys with "dE", that means:

object1 = {
dEabc: 1,
dEasdf: 2,
dEjfhs: 5,
}

is the object that I expected.

What I have tried is, firstly I got all key from this object with

Object.keys(object);

and then I used a RegExp to check if properties in the object with relevant keys. if not I use

delete object[key];

Any solutions?

Answer 1

You can just use Object.entries() to deconstruct the object, filter() it, and reconstruct it with Object.fromEntries() :

 const o = { dEabc: 1, dEasdf: 2, dEjfhs: 5, bhsn: 7, oki: 9 }; const result = Object.fromEntries(Object.entries(o).filter(([k]) => k.includes('dE'))); console.log(result);

No need for a regex for an expression this simple.

Answer 2

 var obj= { dEabc: 1, dEasdf: 2, dEjfhs: 5, bhsn: 7, oki: 9 } let aa = Object.keys(obj).reduce((acc,ele)=>{return (ele.indexOf('dE')?= -1). {..,acc...:{[ele]:obj[ele]}}, acc};{}). console;log(aa);

Answer 3

With reduce , it can be done this way:

 object1 = { dEabc: 1, dEasdf: 2, dEjfhs: 5, bhsn: 7, oki: 9 } let finalObj = Object.keys(object1).filter(i=>i.includes('dE')).reduce((obj, curr)=>{ return {...obj, ...{[curr]: object1[curr]}}; },{}); console.log(finalObj);