如何将 dict 打印为正确的格式？

Question

I previously used course_rolls(records) to make the data to a dictionary below:

{'EMT001': {2286560}, 'FMKT01': {2547053}, 'CSC001': {2955520, 2656583}, 'MGM001': {2928707, 2606735}, 'MTH002': {2786372}, 'FCOM03': {2762453, 2955520, 2564885, 2606735}, 'FMCM02': {2955520, 2928707, 2656583}, 'ENG001': {2571096, 2564885}, 'MKT001': {2571096, 2656583},'AWA001': {2286560}, 'ACC002': {2762453}, 'FMTH01': {2571096}, 'EMT003': {2762453, 2656583}, 'MEA001': {2564885, 2606735}, 'FPHY01': {2564885}, 'FBIO01': {2547053}, 'MTH001': {2286560}, 'ECO002': {2928707, 2786372}, 'FCHM01': {2286560}, 'FCOM01': {2786372}, 'ENG002': {2762453}}

Records variable contains:

[(('EMT001', 'Engineering Mathematics 1'), (2286560, 'Dayton', 'Archambault')), (('FMKT01', 'Marketing'), (2547053, 'Vladimir', 'Zemanek')), (('CSC001', 'Computer Programming'), (2656583, 'Ronny', 'Ridley')), (('MGM001', 'Fundamentals of Management'), (2928707, 'Susanne', 'Eastland')), (('MTH002', 'Mathematics 2'), (2786372, 'Danella', 'Crabe')), (('FCOM03', 'Introduction to Computing'), (2564885, 'Hpone', 'Ganadry')), (('FCOM03', 'Introduction to Computing'), (2762453, 'Phelia', 'Pottle')), (('FMCM02', 'Mass Communication II (Film Studies)'), (2656583, 'Ronny', 'Ridley')), (('ENG001', 'Foundations of Engineering'), (2564885, 'Hpone', 'Ganadry')), (('MKT001', 'Principles of Marketing'), (2571096, 'Shoshanna', 'Shupe')), (('AWA001', 'Engineering Writing Skills'), (2286560, 'Dayton', 'Archambault')), (('FCOM03', 'Introduction to Computing'), (2606735, 'Aaren', 'Enns')), (('ACC002', 'Financial Accounting'), (2762453, 'Phelia', 'Pottle')), (('FMTH01', 'Advanced Mathematics I'), (2571096, 'Shoshanna', 'Shupe')), (('FCOM03', 'Introduction to Computing'), (2955520, 'Bjorn', 'Kakou')), (('EMT003', 'Mathematical Modelling and Computation'), (2762453, 'Phelia', 'Pottle')), (('MEA001', 'Mixed English Programme'), (2564885, 'Hpone', 'Ganadry')), (('MGM001', 'Fundamentals of Management'), (2606735, 'Aaren', 'Enns')), (('MEA001', 'Mixed English Programme'), (2606735, 'Aaren', 'Enns')), (('FPHY01', 'Physics'), (2564885, 'Hpone', 'Ganadry')), (('FBIO01', 'Introduction to Biology'), (2547053, 'Vladimir', 'Zemanek')), (('ENG001', 'Foundations of Engineering'), (2571096, 'Shoshanna', 'Shupe')), (('MKT001', 'Principles of Marketing'), (2656583, 'Ronny', 'Ridley')), (('MTH001', 'Mathematics 1'), (2286560, 'Dayton', 'Archambault')), (('ECO002', 'Introduction to Macroeconomics'), (2786372, 'Danella', 'Crabe')), (('FCHM01', 'Chemistry'), (2286560, 'Dayton', 'Archambault')), (('FCOM01', 'Communication Skills II'), (2786372, 'Danella', 'Crabe')), (('FMCM02', 'Mass Communication II (Film Studies)'), (2928707, 'Susanne', 'Eastland')), (('CSC001', 'Computer Programming'), (2955520, 'Bjorn', 'Kakou')), (('ENG002', 'Engineering Mechanics and Materials'), (2762453, 'Phelia', 'Pottle')), (('EMT003', 'Mathematical Modelling and Computation'), (2656583, 'Ronny', 'Ridley')), (('FMCM02', 'Mass Communication II (Film Studies)'), (2955520, 'Bjorn', 'Kakou')), (('ECO002', 'Introduction to Macroeconomics'), (2928707, 'Susanne', 'Eastland'))]

The program input is: clashes CSC001

Expected output (Command: clashes CSC001):

Clashes with CSC001:
In CSC001 and EMT003
  2656583: 

In CSC001 and FCOM03
  2955520: 

In CSC001 and FMCM02
  2656583: 
  2955520: 

In CSC001 and MKT001
  2656583: 

The result I get (Command: clashes CSC001):

Clashes with CSC001:
In CSC001 and FCOM03  
  2955520: 

In CSC001 and FMCM02  
  2955520: 

In CSC001 and EMT003  
  2656583: 

In CSC001 and FMCM02  
  2656583: 

In CSC001 and MKT001  
  2656583: 

Program code: (clashes function need to fix)

def parse_course_code(commands, records):
    if commands in course_rolls(records).keys():
        print('Clashes with {}:'.format(commands))
        return clashes(commands, records)
    else:
        print("Unknown course code")


def clashes(course_code, records):
    unformatted_course_rolls = course_rolls(records)
    for course, prior_student_number in sorted(unformatted_course_rolls.items()):
        for prior_student_number_single in list(prior_student_number):
            if course_code == course:
                for code, student_number in sorted(unformatted_course_rolls.items()):
                    for num in list(student_number):
                        if prior_student_number_single == num and course != code:
                            print("In {} and {}  ".format(course, code))
                            print("  {}: \n".format(num))

def main():
    while True:
        command = input('Command: ')
        if command == 'quit':
            print('Adios')
            break
        else:
            parse_course_code(commands, records)
main()

Answer 1

The code you provided is very complicated to follow. You should try to use less for loops - it makes the code harder to read, and takes longer to execute (if you were performing something of larger scale). Take a look at my solution below, it prints the result as you would expect and is much easier to read and understand.

Here is the refactored code (note, since you didn't provide the course_roll function, I changed course_roll(records) for the variable course_rolls_records , so I could run it locally.):

def parse_course_code(commands):
    if commands in course_rolls_records.keys():
        print('Clashes with {}:'.format(commands))
        return clashes(commands)
    else:
        print("Unknown course code")


def clashes(course_code):
    numbers_in_course = course_rolls_records[course_code]
    collisions = {}
    for course_check in course_rolls_records.keys():
        numbers_in_course_check = course_rolls_records[course_check]
        if course_check == course_code:
            # This is the course we are querying, we don't need to do anything
            pass
        elif numbers_in_course_check.intersection(numbers_in_course):
            # We enter here if there are common student numbers between courses
            # Note: if there is no intersection, bool of empty set is False
            collisions[course_check] = list(numbers_in_course_check.intersection(numbers_in_course))
            print("In {} and {}  ".format(course_code, course_check))
            for num in collisions[course_check]:
                print("  {}: ".format(num))
            print('\n')

def main():
    while True:
        command = input('Command: ')
        if command == 'quit':
            print('Adios')
            break
        else:
            parse_course_code(command)

main()