[英]Maintain float precision when selecting values in a pandas dataframe using iloc
My code:我的代码:
import pandas as pd
pd.set_option('display.float_format','{:.2f}'.format)
df = pd.Series([500.0, 200.0, 300.0])
df
0 500.00
1 200.00
2 300.00
dtype: float64
df.iloc[1]
200.0
I want df.iloc[1]
to return 200.00, can anyone explain what's happening here and how to get the desired result please.我希望
df.iloc[1]
返回 200.00,任何人都可以解释这里发生了什么以及如何获得所需的结果。
Indexing the way you did will return the actual value at that index, which is type float.以您所做的方式索引将返回该索引处的实际值,即浮点类型。
type(df.iloc[1]) # returns 'numpy.float64'
What you would like to do is print the entire row, like so:您想要做的是打印整行,如下所示:
df.iloc[[1]]
In this case, the index returns a series:在这种情况下,索引返回一个系列:
type(df.iloc[[1]]) # returns 'pandas.core.series.Series'
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