[英]How to associate package-info with class in Byte-buddy?
I create package-info of package foo.bar
and class foo.bar.BarCl
in next code我在下一个代码中创建 package
foo.bar
和 class foo.bar.BarCl
的包信息
public static void main(String[] args) throws ClassNotFoundException, IOException {
DynamicType.Unloaded<?> make = new ByteBuddy().makePackage("foo.bar").make();
DynamicType.Loaded<Object> load = new ByteBuddy()
.subclass(Object.class)
.name("foo.bar.BarCl")
.make()
.include(make)
.load(Main2.class.getClassLoader(), ClassLoadingStrategy.Default.INJECTION);
load.saveIn(new File("folder"));
Class<?> loaded = load.getLoaded();
System.out.println(loaded.getPackage());
}
Class and package info correctly writing in folder: Class 和 package 信息正确写入文件夹:
package foo.bar;
interface $$package-info /* Real name is 'package-info' */ {
}
package foo.bar;
public class BarCl {
public BarCl() {
}
}
But in runtime after injecting this classes i get loaded.getPackage()==null
How i can associate package-info with generated class?但是在运行时注入这些类后,我得到
loaded.getPackage()==null
我如何将包信息与生成的 class 关联?
PS In real task i need to generate package-info with JAXB annotation @XmlSchema
, that specify xml namespace. PS 在实际任务中,我需要使用 JAXB 注释
@XmlSchema
生成包信息,指定 xml 命名空间。 Without it, classes have naming collisions没有它,类就会发生命名冲突
Packages are class loader respobsibility and not defined by a package-info
class.包是 class 加载程序责任,而不是由
package-info
class 定义。 You can define them using the loader DSL .您可以使用加载程序 DSL定义它们。
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