比较两个 Arrays 对象，如果 Javascript 中的值为真，则返回一个新数组

Question

I need to compare 2 arrays

const inviteFriends = [
  {
    userId: 'u12p3',
    name: 'Goku',
    invited: true
  },
  {
    userId: 'uefi3',
    name: 'Vegeta',
    invited: true
  }
]

const allFriends = [
  {
    userId: 'u12p3',
    name: 'Goku',
    invited: false
  },
  {
    userId: 'ufisj',
    name: 'Goten',
    invited: false
  },
  {
    userId: 'uefi3',
    name: 'Vegeta',
    invited: false
  },
]

An if invited is true I need to return a new array.

Something like this:

const newArray = [
  {
    userId: 'u12p3',
    name: 'Goku',
    invited: true
  },
  {
    userId: 'ufisj',
    name: 'Goten',
    invited: false
  },
  {
    userId: 'uefi3',
    name: 'Vegeta',
    invited: true
  },
]

Any idea how can I achieve this? Help please

Answer 1

 const inviteFriends = [ { userId: 'u12p3', name: 'Goku', invited: true }, { userId: 'uefi3', name: 'Vegeta', invited: true } ] const allFriends = [ { userId: 'u12p3', name: 'Goku', invited: false }, { userId: 'ufisj', name: 'Goten', invited: false }, { userId: 'uefi3', name: 'Vegeta', invited: false }, ]; const newArr = allFriends.map((friend) => { const found = inviteFriends.find((invited) => { return invited.userId === friend.userId }); return {...friend, ...found}; }); console.log(newArr);

Answer 2

Use filtering to achieve that:

invitedFriends = allFriends.filter(friend => friend.invited==true);

Answer 3

since you also need the,invited row, so the logic is to replace the same data from invitedFriends to allFriends (compare by id)

we loop on the allfriends then find if allfriend(n).id found on invitedFriend if found then push invitedFriend(found) if not just push the allfriend(n)

so in one line you can use

let x = allFriends.map( af =>  inviteFriends.find( x => x.userId === af.userId) || af );