如果我在 kernel 中添加一个 while 循环，Qemu 会重新启动

Question

I wrote a while loop that hangs when the keyboard controller is not ready:

while(inb(0x64)!=0){

  }

However now qemu restarts everytime I attempt to boot the kernel. Sometimes I can see the vga output for a really short time. I tried to remove the inb, and it still restarts unless I remove it

EDIT:

Here's the complete code:

int *resolution_ptr;


void init_vbe(){
    regs16_t vberegister;
  vberegister.bx=0x4107;
  vberegister.ax=0x4f02;
  int32(0x10,&vberegister);


  *resolution_ptr=1280;
}

void kernel_main(void) 
{

  resolution_ptr=(int*)0x2ff0; /*define the address of the resolution, so that the printstring function can draw the letter correctly*/

  init_vbe ();
    printstring("Kernel sucessfully loaded.");


  while(inb(0x64)!=0){ /*code that cause qemu to restart*/
  }

}

bochs thrown this error when I try to run my kernel in it:

00096454180e[CPU0  ] exception(): 3rd (13) exception with no resolution, shutdown status is 00h, resetting

Also INT32 is from here: https://gist.github.com/carlosascari/35dba95ee3118ebf61f4bd1625f4fa11

Answer 1

Works now by removing sti in int32.