[英]A non-numeric value encountered PHP MYSQL opencart
Warning: A non-numeric value encountered in /home/u914452720/domains/e-gilius.com/public_html/system/storagefnpzt1uybylm/modification/admin/model/catalog/manufacturer.php on line 349Warning: A non-numeric value encountered in /home/u914452720/domains/e-gilius.com/public_html/system/storagefnpzt1uybylm/modification/admin/model/catalog/manufacturer.php on line 349
警告:在第 349 行的 /home/u914452720/domains/e-gilius.com/public_html/system/storagefnpzt1uybylm/modification/admin/model/catalog/manufacturer.php 中遇到非数字值警告:在/home/u914452720/domains/e-gilius.com/public_html/system/storagefnpzt1uybylm/modification/admin/model/catalog/manufacturer.php 在第 349 行
I get this error when I execute delete function: admin/controller/catalog/manufacturer_download.php执行 delete function: admin/controller/catalog/manufacturer_download.php 时出现此错误
function delete(){
// var_dump("I AM IN DELETE");
$this->load->model('catalog/manufacturer');
$postData = array();
if(isset($_POST['submitdelete'])){
// var_dump("DELETE SUBMITTED");
$entryID = $_POST['entryID'];// <-- gotta protect from sql injection.
// var_dump($entryID);
$this->model_catalog_manufacturer->deleteManufacturersDownload($entryID);
}
}
If I var_dump($entryID) it gives result: string(1) "5"如果我 var_dump($entryID) 它给出结果: string(1) "5"
admin/model/catalog/manufacturer.php admin/model/catalog/manufacturer.php
public function deleteManufacturersDownload($id){
$this->db->query("DELETE FROM ". DB_PREFIX . "manufacturer_downloads WHERE id =" + "'"+$id+"'");
return "success";
}
Where I made mistake?我在哪里犯错了?
You are using + in query that is wrong not need that use following code您在查询中使用 + 是错误的,不需要使用以下代码
$this->db->query("DELETE FROM ". DB_PREFIX . "manufacturer_downloads WHERE id = '$id'");
You are mixing up the string concatenation:您正在混淆字符串连接:
change改变
$this->db->query("DELETE FROM ". DB_PREFIX . "manufacturer_downloads WHERE id =" + "'"+$id+"'");
to至
$this->db->query("DELETE FROM ". DB_PREFIX . "manufacturer_downloads WHERE id =" . "'" . $id . "'");
The error comes from trying to add string and numbers together:该错误来自尝试将字符串和数字相加:
echo "FOO" + 1337; // Warning: A non-numeric value encountered in[...]
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