我将如何遍历数组以查看用户输入变量（数字）是否等于数组中的一个元素并用“@”替换该元素

Question

//my array(arrayAlphabetizer) is an int[] with random int with a capacity = the users name and surname
//allow the user to enter a value from arrayAlphabetizer element to search for

Scanner value = new Scanner(System.in);
System.out.println("please enter a value from the array to search for");
String search = input.nextLine();

//change input into int
int number = Integer.parseInt(search);

//loop through the array to find the value
for (int i = number; i <= arrayAlphabetizer.length; number++) {

    if (i <= number) {
        arrayAlphabetizer[i] = 0;
        System.out.println(Arrays.toString(arrayAlphabetizer));
    } else {
        System.out.print(i);
    }
}

I've tried this and multiple other methods but nothings is working

Answer 1

You are setting i = to number at the start of your loop. Your if statement will be executed in the first iteration of the loop. I think you want to start your loop at i = 0. Also I needs to be less than the length of the array, not less than or equal to.

for(int i = 0; i < array.length; i++){
     if(array[i] == number)
          System.out.println(**whatever you want to print**);
     else
          System.out.println(**whatever you want to print);

}

You are trying to add a char into an int array which does not work. Are you sure you need to do that?

I hope this helps. Your question was a bit unclear and I cannot comment yet to ask for clarification so just respond if you have questions.

Answer 2

int number = Integer.parseInt(search);

for (int i = 0; i <= arrayAlphabetizer.length; number++) {

if (number == arrayAlphabetizer[i]) 
{
    arrayAlphabetizer[i] = 0;
    System.out.println(Arrays.toString(arrayAlphabetizer));
} else {
    System.out.print(i);
}

}