Python - 当另一列中的数字大于之前的数字时，将列中的 x 值保存到列表中

Question

(I'm new to this so I might not know the best way to formulate this question but here goes)

I'm using pandas btw!

I am looking for a construct to each time save x values (let's say x=3 so three values) from one column to a list when a number in another column is bigger than the number before. First number should not be considered. Important to note that there are also missing data in the number column (NaN).

NumberColumn   Value
23             4
23             5
NaN            8
24             6    # <--
24             23   # <--
24             26   # <--
24             11
25             2    # <--
25             1    # <--
25             3    # <--
25             5
Nan            9
26             4    # <--
26             6    # <--
NaN            9    # <--
26             12

Hopefully in the end the new list contains:

List1 = [6,23,26,2,1,3,4,6,9]

But also they might overlap so:

NumberColumn       Value
    27             4
    28             5    # <--
    NaN            8    # <--
    29             6    # <--   <-- overlap!
    29             23         # <--
    29             26         # <--

Hopefully here the list will contain:

List1 = [5, 8, 6, 6, 23, 26]

Thanks for helping me out !

Answer 1

With the assumption that numbers cannot be smaller than 0:

list1 = []
x=3

df.fillna(value=0, inplace=True)
for i in range(1, len(df)):
    if df.loc[i, 'NumberColumn']>df.loc[i-1, 'NumberColumn']:
        list1 = list1 + df.loc[i:i+x-1, 'Value'].values.tolist()
print(list1)

As a function:

def createList(df, x):
    list1 = []
    df.fillna(value=0, inplace=True)
    for i in range(1, len(df)):
        if df.loc[i, 'NumberColumn']>df.loc[i-1, 'NumberColumn']:
            list1 = list1 + df.loc[i:i+x-1, 'Value'].values.tolist()
    return list1

list1 = createList(df, x=3)
print(list1)