[英]Selecting characters from command and replacing some of them
I have this result from a NetApp query我从 NetApp 查询中得到了这个结果
Object: nfsv4_diag
Instance: nfs4_diag
Start-time: 6/4/2020 16:55:40
End-time: 6/4/2020 16:55:40
Scope: NODE1
Counter Value
-------------------------------- --------------------------------
storePool_ByteLockAlloc 0
storePool_ClientAlloc 60
storePool_CopyStateAlloc 0
storePool_DelegAlloc 0
storePool_DelegStateAlloc 0
storePool_LayoutAlloc 0
storePool_LayoutStateAlloc 0
storePool_LockStateAlloc 0
storePool_OpenAlloc 86
storePool_OpenStateAlloc 86
storePool_OwnerAlloc 10
storePool_StringAlloc 70
Object: nfsv4_diag
Instance: nfs4_diag
Start-time: 6/4/2020 16:55:40
End-time: 6/4/2020 16:55:40
Scope: NODE2
Counter Value
-------------------------------- --------------------------------
storePool_ByteLockAlloc 1246
storePool_ClientAlloc 29
storePool_CopyStateAlloc 0
storePool_DelegAlloc 0
storePool_DelegStateAlloc 0
storePool_LayoutAlloc 0
storePool_LayoutStateAlloc 0
storePool_LockStateAlloc 468
storePool_OpenAlloc 811
storePool_OpenStateAlloc 811
storePool_OwnerAlloc 519
storePool_StringAlloc 548
Object: nfsv4_diag
Instance: nfs4_diag
Start-time: 6/4/2020 16:55:40
End-time: 6/4/2020 16:55:40
Scope: NODE3
Counter Value
-------------------------------- --------------------------------
storePool_ByteLockAlloc 165
storePool_ClientAlloc 27
storePool_CopyStateAlloc 0
storePool_DelegAlloc 0
storePool_DelegStateAlloc 0
storePool_LayoutAlloc 0
storePool_LayoutStateAlloc 0
storePool_LockStateAlloc 135
storePool_OpenAlloc 272
storePool_OpenStateAlloc 272
storePool_OwnerAlloc 152
storePool_StringAlloc 179
And I would like to transform it to something like:我想将其转换为:
NODE1.storePool_ByteLockAlloc=0;NODE1.storePool_ClientAlloc=60;NODE1.storePool_CopyStateAlloc=0;............NODEn.storePool_ByteLockAlloc=165;
For all the nodes I have from the output (not only 3).对于我从 output 获得的所有节点(不仅是 3 个)。
I have tried replacing the output using this:我尝试使用以下方法替换 output:
output.replace(' ', '').replace('Alloc', 'Alloc=').replace('\r','').replace('\n',' ')
But this is not giving me the result that I need.但这并没有给我我需要的结果。
Some ideas?一些想法?
Thanks a lot in advance for your help.非常感谢您的帮助。
If you capture the output into one long string, you can use a regex to find the lines of interest and parse them into the format you're requesting:如果您将 output 捕获到一个长字符串中,您可以使用正则表达式查找感兴趣的行并将它们解析为您请求的格式:
import re
output = """
Object: nfsv4_diag
Instance: nfs4_diag
Start-time: 6/4/2020 16:55:40
End-time: 6/4/2020 16:55:40
Scope: NODE1
Counter Value
-------------------------------- --------------------------------
storePool_ByteLockAlloc 0
storePool_ClientAlloc 60
storePool_CopyStateAlloc 0
storePool_DelegAlloc 0
.
.
.
"""
rv = []
current_node = None
for match in re.findall(r'Scope: (NODE\d+)|(storePool_.*)', output):
node, metric = match
if node and current_node != node:
current_node = node
if current_node and metric:
name, value = metric.strip().split()
rv.append(f'{current_node.strip()}.{name}={value}')
print(';'.join(rv))
Output: Output:
NODE1.storePool_ByteLockAlloc=0;NODE1.storePool_ClientAlloc=60;NODE1.storePool_CopyStateAlloc=0;NODE1.storePool_DelegAlloc=0;...
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