在 R 中拟合线性 model 以获得各种值

Question

In this experiment, four different diets were tried on animals. Then researchers measured their effects on blood coagulation time.

 ## Data :
    coag diet
 1    62    A
 2    60    A
 3    63    A
 4    59    A
 5    63    B
 6    67    B
 7    71    B
 8    64    B
 9    65    B
 10   66    B
 11   68    C
 12   66    C
 13   71    C
 14   67    C
 15   68    C
 16   68    C
 17   56    D
 18   62    D
 19   60    D
 20   61    D
 21   63    D
 22   64    D
 23   63    D
 24   59    D

I am trying to fit a linear model for coag~diet by using the function lm in R Results should look like the following:

> modelSummary$coefficients
                 Estimate Std. Error       t value     Pr(>|t|)
(Intercept)  6.100000e+01   1.183216  5.155441e+01 9.547815e-23
dietB        5.000000e+00   1.527525  3.273268e+00 3.802505e-03
dietC        7.000000e+00   1.527525  4.582576e+00 1.805132e-04
dietD       -1.071287e-14   1.449138 -7.392579e-15 1.000000e+00

My code thus far does not look like results:

coagulation$x1 <- 1*(coagulation$diet=="B")
coagulation$x2 <- 1*(coagulation$diet=="C")
coagulation$x3 <- 1*(coagulation$diet=="D")
modelSummary <- lm(coag~1+x1+x2+x3, data=coagulation)

Answer 1

"diet" is a character variable and is treated as a factor. So you may leave out the dummy coding and just do:

summary(lm(coag ~ diet, data=coagulation))$coefficients
#                 Estimate Std. Error      t value     Pr(>|t|)
# (Intercept) 6.100000e+01   1.183216 5.155441e+01 9.547815e-23
# dietB       5.000000e+00   1.527525 3.273268e+00 3.802505e-03
# dietC       7.000000e+00   1.527525 4.582576e+00 1.805132e-04
# dietD       2.991428e-15   1.449138 2.064281e-15 1.000000e+00

Even if "diet" were a numeric variable and you want R to treat it as a categorical rather than a continuous variable no dummy coding is needed, you would just add it as + factor(diet) into the formula.

As you see, also 1 + is redundant since lm calculates the (Intercept) by default. To omit the intercept, you may do 0 + (or - 1 ).

Answer 2

That presentation is a property of summary(modelSummary) (class summary.lm ), not modelSummary (class lm ).

summary(modelSummary)$coefficients
#                 Estimate Std. Error      t value     Pr(>|t|)
# (Intercept) 6.100000e+01   1.183216 5.155441e+01 9.547815e-23
# x1          5.000000e+00   1.527525 3.273268e+00 3.802505e-03
# x2          7.000000e+00   1.527525 4.582576e+00 1.805132e-04
# x3          2.991428e-15   1.449138 2.064281e-15 1.000000e+00

Answer 3

You may also consider coding diet in this manner

coagulation$diet <- factor(coagulation$diet)

modelSummary<-lm(coag~diet,coagulation)

summary(modelSummary)

Call:
lm(formula = coag ~ diet, data = coagulation)

Residuals:
   Min     1Q Median     3Q    Max 
 -5.00  -1.25   0.00   1.25   5.00 

Coefficients:
             Estimate Std. Error t value Pr(>|t|)    
(Intercept) 6.100e+01  1.183e+00  51.554  < 2e-16 ***
dietB       5.000e+00  1.528e+00   3.273 0.003803 ** 
dietC       7.000e+00  1.528e+00   4.583 0.000181 ***
dietD       2.991e-15  1.449e+00   0.000 1.000000    
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1