如何将 function 应用于列表中的每个元素，然后制作输出列表？

Question

Im trying to get prime factors by factorizing a number and adding the factors to list1 , and then factorizing every number in list1 using the same method from before and adding to list2 , so any prime factor will have a list length of 2 (If the number is a square number it prints out the square root twice, but since it is not a prime, it doesn't matter).

I don't know how to get it to apply my factors() function to every element in the list1 and make a list of all the factorized factors I've made.

import math
list1 = []
list2 = []
def factors(num1):

    for x in range(1, int(math.sqrt(num1) + 1)):
        if num1 % x == 0:
            list2.append(int(x))
            list2.append(int(num1/x))
            list2.sort()

print("enter a number:")
number = int(input())

for m in range(1, int(math.sqrt(number) + 1)):
    if number % m == 0:
        list1.append(int(m))
        list1.append(int(number/m))
        list1.sort()

for y in list1:
    factors(y)
print(list2)

desired output if 20 was the input

((1,1),(1,2),(1,2,2,4)(1,5),(1,2,5,10),(1,2,4,5,10,20))

Answer 1

You can do this using list comprehension like so. I modified the factors function slightly to return the list.

import math

def factors(num):
     fact = []
     for x in range(1, int(math.sqrt(num)+1)):
         if num % x == 0:
             fact.append(x)
             fact.append(int(num/x))
     fact.sort()
     return fact

print("enter a number:")
number = int(input())

list1 = factors(number)
list2 = [factors(f) for f in list1]

Result for 20:

[[1, 1], [1, 2], [1, 2, 2, 4], [1, 5], [1, 2, 5, 10], [1, 2, 4, 5, 10, 20]]

Answer 2

In factors function, you are appending the factors themselves to list2 but as you want nested list of factors, you should create another list and append that to list2 instead. Changed code would look something like this.

import math
list1 = []
list2 = []
def factors(num1):
    factor_list = []
    for x in range(1, int(math.sqrt(num1) + 1)):
        if num1 % x == 0:
            factor_list.append(int(x))
            factor_list.append(int(num1/x))
    factor_list.sort()
    list2.append(factor_list)

print("enter a number:")
number = int(input())

for m in range(1, int(math.sqrt(number) + 1)):
    if number % m == 0:
        list1.append(int(m))
        list1.append(int(number/m))
        list1.sort()

for y in list1:
    factors(y)
print(list2)

Also, since you've already wrote the factors function, you can use it for factorizing the input number itself instead of writing the same code again. So a better version of the same code is:

import math


def factors(num1):
    factor_list = []
    for x in range(1, int(math.sqrt(num1) + 1)):
        if num1 % x == 0:
            factor_list.append(int(x))
            factor_list.append(int(num1/x))
    factor_list.sort()
    return factor_list

print("enter a number:")
number = int(input())

list1 = factors(number)
list2 = [factors(x) for x in list1]

print(list2)

Following up on the comment, if you want to include only on those elements which have length 2, you can use another list comprehension for that:

list2 = [x for x in list2 if len(x)==2]