[英]react-native state variable in logical statement not working
I want to render click button only when the count is less than 4, otherwise print "helo there".我只想在计数小于 4 时才呈现单击按钮,否则打印“helo there”。 The variable count is a state variable with value zero initially;
变量 count 是一个 state 变量,初始值为 0; which increments as button is clicked.
随着按钮被点击而增加。 But the output is "helo there" only though count is zero.. Why it is so...??
但是 output 只是“helo there”,尽管计数为零。为什么会这样......??
import * as React from 'react';
import {Component} from 'react';
import { Text, View, Button } from 'react-native';
import { NavigationContainer } from '@react-navigation/native';
import { createStackNavigator } from '@react-navigation/stack';
export default class App extends React.Component {
constructor(props) {
super(props);
this.state = {
count: 0
};
}
render() {
if(this.props.count<4){
return (
<View>
<div>
<p>You clicked {this.state.count} times</p>
<button onClick={() => this.setState({ count: this.state.count + 1 })}>
Click me
</button>
</div>
</View>
);
}
else
{
return(<View><Text>{this.state.count}</Text></View>);
}
}
}
Since your count
is inside your state, you should change the if statement to:由于您的
count
在您的 state 内,您应该将 if 语句更改为:
if(this.state.count<4){
you are using this.props.count, instead of props.count, use this.state.count<4
in if statement.您正在使用 this.props.count,而不是 props.count,在 if 语句中使用
this.state.count<4
。 props are used to get properties from parent component. props 用于从父组件获取属性。
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