MySQL: select 具有特定字段值的多行

Question

I'm having a users_conversations table contains a conversation_id and a user_id to tell which users are in the same conversation. I want to find any conversation_id which has user_id 76 and user_id 146 (which are ids 28, 31 and 32. These ids are not unknown to me. I just have both users ids) I tried

select * from users_conversations where user_id = 146 or user_id = 76 GROUP BY conversation_id

but I get

#1055 - Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 
'forums.users_conversations.user_id' which is not functionally dependent on columns in GROUP BY clause; 
this is incompatible with sql_mode=only_full_group_by

How can I do that?

Answer 1

select * from users_conversations
where conversations_id in (select conversations_id from user_conversations where user_id=76) 
AND conversations_id in (select conversations_id from user_conversations where user_id=146)

Answer 2

You can filter the table for these users, group by conversation_id and set the condition in the having clause:

select conversation_id
from users_conversations
where user_id in (76, 146)
group by conversation_id
having count(distinct user_id) = 2

You may omit distinct if there is no case of duplicate users for each conversation_id .

Answer 3

Did you mean instead:

select * from users_conversations where user_id = 146 or user_id = 76

Why do you want to use group?