关闭通过 pty.openpty() 创建的 PseudoTTY

Question

I'm using pty.openpty() to fool a subprocess that changes its behaviour based on isatty() , vaguely like this:

import pty
import subprocess

master, slave = pty.openpty()
with subprocess.Popen(cmd, stdin=slave) as process:
    stdout, stderr = process.communicate()

However, after doing this many many times (as part of automated testing), I get:

E           OSError: [Errno 24] Too many open files

../../miniconda/envs/aclimatise-test/lib/python3.7/subprocess.py:1393: OSError

and

E       OSError: out of pty devices
../../miniconda/envs/aclimatise-test/lib/python3.7/pty.py:59: OSError

For some reason the pty module documentation doesn't tell me how or when to close the pseudoTTYs that I'm allocating. How and when should I do so? Or am I using pty in entirely the wrong way?

If it helps, I'm on Python 3.6+, using Linux (which I think is a requirement for using this module).

Answer 1

You can use os.close to close master and slave.

os.close(fd) Close file descriptor fd.

Note This function is intended for low-level I/O and must be applied to a file descriptor as returned by os.open() or pipe(). To close a “file object” returned by the built-in function open() or by popen() or fdopen(), use its close() method.

Answer 2

try setting close_fds=True in subprocess.Popen

subprocess.Popen(
  # ...
  close_fds=True,
)