将 CSV 文件送入 Bash 中的变量进行解析

Question

For each row in a CSV file, I'd like to extract a field and reposition it in the row using Bash. The row is a URL and I am using / as a delimiter.

This is the starting file (start.csv):

https://docs.website.com/12-3/articles/guide-1/article-1.html
https://docs.website.com/12-2/articles/guide-2/article-5.html
https://docs.website.com/12-1/articles/guide-3/article-6.html

For later reference, the URL is https://{url}/{version}/irrelevant/{guide}/irrelevant.html .

The desired output is (end.csv):

url,name,tag,version,guide,views
https://docs.website.com/12-3/articles/guide-1/article-1.html,,,12-3,guide-1,0
https://docs.website.com/12-2/articles/guide-2/article-5.html,,,12-2,guide-2,0
https://docs.website.com/12-1/articles/guide-3/article-6.html,,,12-1,guide-3,0

I've unsuccessfully tried many variations of:

file="start.csv"
var="$(<<<"${file}" cut -d'/' -f4)"

sed -e "s|$|,$var,,,,0|g" < start.csv > end.csv

However this successfully produces a column with the version:

cut -d'/' -f4 < start.csv

Somewhere my logic is seriously flawed. Is anyone able to help me spot my problem? Thank you.

Answer 1

It is easier, using awk :

awk -F/ -v OFS=, '{print $0, "", "", $4, $6, 0}' file

https://docs.website.com/12-3/articles/guide-1/article-1.html,,,12-3,guide-1,0
https://docs.website.com/12-2/articles/guide-2/article-5.html,,,12-2,guide-2,0
https://docs.website.com/12-1/articles/guide-3/article-6.html,,,12-1,guide-3,0