第二次调用 Tone.JS function 不起作用

Question

When I press the button the first time, it plays back the list of notes as expected, but not the second time.当我第一次按下按钮时，它会按预期播放笔记列表，但第二次不会。 My console logging suggests that the second time around the function is called in the same way, but perhaps I am missing something?我的控制台日志记录表明第二次以相同的方式调用 function，但也许我遗漏了什么？ Why will this not play the sequence of notes the second time?为什么这不会第二次播放音符序列？

I tried eg Tone.Transport.start(0) among other potential solutions but this didn't solve the problem.我在其他可能的解决方案中尝试了例如 Tone.Transport.start(0) 但这并没有解决问题。

HTML HTML

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
    <script src= "www/js/Tone.js"></script>
    <script src= "main.js"></script>
</head>
<body>

    <button onclick="playSeq([60, 61, 62], false, this.id, 'tone');">Play</button>

</body>
</html>

Javascript Javascript

function playSeq (note_list, hidePlay, id, sound) {


  midi_list = note_list.map(x => Tone.Frequency(x, "midi").toNote());
  last_note = midi_list.length;
  count = 0;
  var pattern = new Tone.Sequence(function(time, note){

  triggerNote(sound, note, 0.25);
  count = count + 1;

  if (count === last_note) {
  console.log("finished!");
  }

  }, midi_list);

  pattern.start(0).loop = false;

  console.log(Tone.Transport);
  // begin at the beginning
  Tone.Transport.start();


}

Answer 1

I had to call.stop() on the Transport and the Tone sequence objects after the finished playing back to solve the problem:回放结束后，我不得不在 Transport 和 Tone 序列对象上调用 .stop() 来解决问题：

if (count === last_note) {
      pattern.stop();
      Tone.Transport.stop();
    }

第二次调用 Tone.JS function 不起作用

问题描述

1 个解决方案

解决方案1
0 已采纳 2020-06-11 07:48:19

第二次调用 Tone.JS function 不起作用

问题描述

1 个解决方案

解决方案1 0 已采纳 2020-06-11 07:48:19

解决方案1
0 已采纳 2020-06-11 07:48:19