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模板化方法中的运算符重载

[英]Operator overload in a templated method

I have a class (with irrelevant details stripped):我有一个 class (删除了不相关的细节):

template <typename... Ts>
class ParameterPack
{
  private:
    std::tuple<Ts...> parameters;


  public:
    ParameterPack<Ts...>(const char* pVariableName)
    {
        /// Irrelevant extra details
    }


    template <typename T, std::size_t idx>
    T getValue()
    {
        return std::get<idx>(parameters);
    }


    template <std::size_t idx>
    void updateValue(unsigned int val)
    {
        std::get<idx>(parameters) = val;

        /// Irrelevant extra details
    }

template <class... Ts>
static ParameterPack<Ts...>* extractParameterPack(const char* name)
{
    // Construnt the new parameter extractor
    auto paramPack = new ParameterPack<Ts...>(name);

    /// Irrelevant extra details

    return paramPack;
}
};

Whose primary function is to parse a string into its data elements (held internally in a private tuple).其主要 function 是将字符串解析为其数据元素(内部保存在私有元组中)。 I am trying to improve the ergonomics of the updateValue and getValue interface however.但是,我正在尝试改进updateValuegetValue接口的人体工程学。

I would like to overload [] to be to change the calling syntax from:我想重载[]以更改调用语法:

    auto val1 = parameterPack->getValue<float, 1>();

to:至:

    auto test2 = parameterPack[1];

But my overloads never take effect.但是我的重载永远不会生效。 I think the overload should look something close to:我认为重载应该看起来接近:

or possibly:或者可能:

    template <typename T, std::size_t idx>
    const T& operator[](std::size_t _idx) const
    {
        std::cout << "yay, overloading " << idx << std::endl;
        return idx * 1.0;
        // return std::get<idx>(parameters);
    }

If I call operator[] directly, it executes my overload, but not if I just try to use the [] operator normally.如果我直接调用operator[] ,它会执行我的重载,但如果我只是尝试正常使用[]运算符则不会。

It's not possible to specialize a templated operator[] on the index, since the index is a run-time property.由于索引是运行时属性,因此不可能在索引上专门化模板化operator[]

For this reason std::tuple has a get<idx>() member function instead of operator[] (see this related question ).出于这个原因, std::tuple有一个get<idx>()成员 function 而不是operator[] (参见这个相关问题)。

In addition, it's not possible to deduce a function (or operator) return type from an assignment.此外,不可能从赋值中推断出 function(或运算符)返回类型。

So nether T nor idx in template <typename T, std::size_t idx> operator[]... can be deduced, unfortunately, which excludes it from the set of viable overload candidates.因此,不幸的是, template <typename T, std::size_t idx> operator[]...中的 Nether Tidx都可以推导出来,这将其排除在可行的重载候选集之外。

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