如何使用 django rest 框架创建 Django API？

Question

i am in a situation where i need to create a django api which on call from frontend gives a response fetched internally from some other source but not from serializers and models . Currently i am using django rest framework to create api like below

MODELS

# Create your models here.
class submission(models.Model):
    # fixed fields to show on today panel/pending panel
    email_id = models.CharField(max_length=200, primary_key=True)
    email_sender = models.CharField(max_length=200, null=True, blank=True)


def __str__(self):
        return self.email_id

SERIALIZERS

class UserSerializer(serializers.ModelSerializer):
    class Meta:
        model = submission
        fields = ('__all__')

VIEWS

class SAMPLE(viewsets.ModelViewSet):
    queryset = submission.objects.all()
    serializer_class = UserSerializer

URLS

router = DefaultRouter()
# user table
router.register('user_table_all_data', SAMPLE, basename='user_table_all_data')

and it works as charm, but in order to work with django rest framework i always need to call like this 1. Create model or use existing model, 2. Create serializers,3. Create Views,4. Create URLs 2. Create serializers,3. Create Views,4. Create URLs 2. Create serializers,3. Create Views,4. Create URLs ,

But what if i dont want to use models say for example i want to show data from other source say which contains a sample json like below

sampleData = {"Name":"RAJNISH","Age":32,"ADDRESS":"India"}

so if my API is say 'sample/someid (not pk)'

returns response as

{"Name":"RAJNISH","Age":32,"ADDRESS":"India"}

how can i do this in django rest framework?

Answer 1

Use Function based views instead of Class based views

def sample(request):
    return Response(data={"Name":"RAJNISH","Age":32,"ADDRESS":"India"})