[英]Flutter: How to show and hide the Lottie animation
I already success to show the Lottie like below:我已经成功地展示了 Lottie,如下所示:
But the question is, how to trigger to show and hide the Lottie with a button?但问题是,如何通过按钮触发显示和隐藏 Lottie? For example, the Lottie is not showing, but when I clicking Show Lottie button
, the Lottie will show, and when I clicking Hide Lottie button
, the Lottie will hide.例如,Lottie 没有显示,但是当我单击Show Lottie button
时,Lottie 会显示,当我单击Hide Lottie button
时,Lottie 会隐藏。
This is my full code:这是我的完整代码:
import 'package:flutter/material.dart';
import 'package:lottie/lottie.dart';
void main() {
runApp(MyApp());
}
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return MaterialApp(
home: Scaffold(
appBar: AppBar(
title: Text('Lottie Flutter'),
),
body: Container(
width: double.infinity,
child: Column(
mainAxisSize: MainAxisSize.max,
mainAxisAlignment: MainAxisAlignment.spaceEvenly,
children: <Widget>[
SizedBox(
width: 50,
height: 50,
child: Lottie.asset(
'assets/10219-notification-dot.json',
),
),
Row(
mainAxisSize: MainAxisSize.max,
mainAxisAlignment: MainAxisAlignment.spaceEvenly,
children: <Widget>[
RaisedButton(
onPressed: () {},
child: Text('Show Lottie'),
),
RaisedButton(
onPressed: () {},
child: Text('Hide Lottie'),
),
],
),
],
),
),
),
);
}
}
I solved this with using setState
and Visibility
widget, this is my code:我使用setState
和Visibility
小部件解决了这个问题,这是我的代码:
import 'package:flutter/material.dart';
import 'package:lottie/lottie.dart';
void main() {
runApp(MyApp());
}
class MyApp extends StatefulWidget {
@override
_MyAppState createState() => _MyAppState();
}
class _MyAppState extends State<MyApp> {
var _isShow = false;
@override
Widget build(BuildContext context) {
return MaterialApp(
home: Scaffold(
appBar: AppBar(
title: Text('Lottie Flutter'),
),
body: Container(
width: double.infinity,
child: Column(
mainAxisSize: MainAxisSize.max,
mainAxisAlignment: MainAxisAlignment.spaceEvenly,
children: <Widget>[
SizedBox(
width: 50,
height: 50,
child: Visibility(
visible: _isShow,
child: Lottie.asset(
'assets/10219-notification-dot.json',
),
),
),
Row(
mainAxisSize: MainAxisSize.max,
mainAxisAlignment: MainAxisAlignment.spaceEvenly,
children: <Widget>[
RaisedButton(
onPressed: () {
setState(() {
_isShow = true;
});
},
child: Text('Show Lottie'),
),
RaisedButton(
onPressed: () {
setState(() {
_isShow = false;
});
},
child: Text('Hide Lottie'),
),
],
),
],
),
),
),
);
}
}
use a showDialogue method.使用 showDialogue 方法。 child -> GestureDetector, which when tapped do a pop. child -> GestureDetector,当点击它时会弹出。
Code is below:代码如下:
showDialog(
context: context,
builder: (context) {
return GestureDetector(
onTap: () {
Navigator.pop(context);
},
child: Lottie.asset('assets/animations/success.json',
repeat: false, animate: true),
);
});
});
You can use a bool and if else condition to show it.您可以使用 bool 和 if else 条件来显示它。 Below code can give an idea perhaphs.下面的代码可以给出一个想法。
var show = true;
...
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return MaterialApp(
....
show ?? Lottie.asset(
'assets/10219-notification-dot.json',
),
....
RaisedButton(
onPressed: () {
setState(){show = true}
},
child: Text('Show Lottie'),
),
RaisedButton(
onPressed: () {
setState(){show = false}
},
child: Text('Hide Lottie'),
),
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