How to take query string from the request URL passed as string in java and ignore the rest of the URL

Question

The URL "localhost:9005/index.jsp?accountno=20&password=1234&username=abcd" is passed as a string to a Java file and from here I need to ignore till "?" and store the rest as a string in java.Can anyone help me with this.

Answer 1

Regex is a good option or you can also manipulate URLs using java.net.URL class:

URL url = new URL("http://" + "localhost:9005/index.jsp?accountno=20&password=1234&username=abcd");

System.out.println(url.getPath()); // prints: /index.jsp
System.out.println(url.getQuery()); // prints: accountno=20&password=1234&username=abcd

Answer 2

Regex replacement would be one option here:

String url = "localhost:9005/index.jsp?accountno=20&password=1234&username=abcd";
String query = url.replaceAll("^.*?(?:\\?|$)", "");
System.out.println(query);

This prints:

accountno=20&password=1234&username=abcd

Answer 3

String#substring

public class Main {
    public static void main(String[] args) {
        String url = "localhost:9005/index.jsp?accountno=20&password=1234&username=abcd";
        String paramsStr = url.substring(url.indexOf("?") + 1);
        System.out.println(paramsStr);
    }
}

Output:

accountno=20&password=1234&username=abcd

Answer 4

You can use .split()

String url = "localhost:9005/index.jsp?accountno=20&password=1234&username=abcd";
String queryString = url.split("\\?")[1];