如何将 std::process::Command 格式化为用于调试的字符串

Question

Working on my first rust app, and it issues a number of commands via std::process::Command . If one of these is incorrect I'd like to see what it is, and to have it look pretty on the command line.

Currently I have code that looks like this (simplified):

let mut command = std::process::Command::new("ls");
command.arg("-la");
println!("{:?}", command)

This is alright, but it encloses everything in quotes when it prints the string. The output looks like: "ls" "-la" .

How can I format this so that it doesn't enclose each arg in double quotes, but instead produces a command that is easy to read? Something like: ls -la .

I saw a related issue , but it comes to the same mediocre solution.

Answer 1

Command adds the quotes because, while they're "ugly," they never break a command. On the other hand, not having them can, Parsing whether you need them or not, including all edge cases. can get surprisingly complicated.

If you have a tightly controlled set of use cases, and you are certain that you don't need them, then just remove them:

let mut command = std::process::Command::new("ls");
command.arg("-la");
println!("{}", format!("{:?}", command).replace("\"", ""));