使用 Python 使用 ADB 列出文件

Question

I have a list of files under a directory in my Android device which I want to list, however I only want files without a dot(that is - no hidden files and files with explicit extensions).

I can do that in the mobile device with find :

find /mydir -type f -not -name *.*

And I can do the same with adb from my host (here I need the \" to protect my regex)

adb shell find /mydir -type f -not -name \"*.*\"

However I don't have a way to get it working in Python script triggered from my host. What I did is:

list_command = [
            'adb',
            'shell',
            'find',
            '/mydir'
            '-type',
            'f',
            '-not',
            '-name',
            r'\'*\.*\''
        ]
subprocess.check_output(list_command)
            .decode()
            .splitlines()

It actually gave me all the files regardless of whether a dot is presented in the path. What is the right way to run this adb command in Python?

Answer 1

Since you are still passing a glob, not a regex, you should not escape the dot characters, use "'*.*'" :

list_command = [
            'adb',
            'shell',
            'find',
            '/mydir'
            '-type',
            'f',
            '-not',
            '-name',
            "'*.*'"
        ]

Just use it inside single quotes. Note you do not need to escape single quotes in a double quoted string literal, "'*.*'" is cleaner than the corresponding '\'*.*\'' single quoted string literal.