powershell 生成包含所有其他文件夹名称的列表

Question

let's say i have an array with folders name like this $list=@("folder1","folder2","folder3") and I want to generate a second list with all the others folders in that path but exclude my list. How can I do that?

Answer 1

Use the -exclude switch of Get-ChildItem .

$array = @("Thing1", "Thing2", "Thing3")
GCI -Path "Directory Name" -Exclude $array

And if you only want folders to show you can add the -Directory switch

GCI -Path "Directory Name" -Exclude $array -Directory