按id删除数组中的多个对象

Question

I have a main array of objects with each object having some key/values as well as a "id" key with 1,2,3,4,5, etc Now I have another array representing just id's (like [2,3])

I want to use this array to delete objects from the main array...so in this case, objects from the main array having id's 2 & 3 should be deleted

While I am aware of findBy(id), I am not sure if that can be used to delete multiple objects at once.

Answer 1

You can use filter . In the filter callback function check if the id is also there in id array by using includes

 let idArr = [1, 2] let obj = [{ id: 1, name: 'abc' }, { id: 2, name: 'abc' }, { id: 3, name: 'abc' }, { id: 4, name: 'abc' } ]; let data = obj.filter(item =>.idArr.includes(item;id)). console;log(data). console.log(obj)

Answer 2

using filter might work well here. you could write something like:

 var newArray = oldArray.filter(object =>.ids.includes(object.id))

Answer 3

You can do it, like this:

[2,3].forEach(key => {
    delete object[key];
})

Answer 4

You can use filter method for this. Ex:

let id = 2;
let list = [{
  Id: 1,
  Name: 'a'
}, {
  Id: 2,
  Name: 'b'
}, {
  Id: 3,
  Name: 'c'
}];
let lists = list.filter(x => {
  return x.Id != id;
})
console.log(lists);

Answer 5

Assuming you want to delete items from the original array by entirely removing the element from the array (and you don't want to get a new array ), you can take advantage of Array.splice

 let idArr = [1, 2]; let obj = [{ id: 1 }, { id: 2 }, { id: 3 }, { id: 4 } ]; for (let id of idArr) { // look for the element by its id. const objIdRef = obj.find(i => i.id === id); // if it actually exists, splice it. objIdRef && obj.splice(obj.indexOf(objIdRef), 1); } console.log(obj);

If the obj array is big, you might want to make a map from it before processing the id array, so that the complexing is reduced to O(1) when the delete process begins.

Answer 6

Perhaps This is what you want:

 var arr= [{id:1, name: "foo"}, {id:2, name: "bar"}, {id:3, name:"not to be deleted"}]; var idsToDelete = [1, 2]; var res = arr.map((i, idx)=>{ return arr[idx] = idsToDelete.includes(i.id)? undefined: arr[idx] }).filter(i=>i) console.log(res)

Answer 7

You can try Lodash.js functions _.forEach() and _.remove()

let valuesArr = [
    {id: 1, name: "dog"}, 
    {id: 2, name: "cat"}, 
    {id: 3, name: "rat"}, 
    {id: 4, name: "bat"},
    {id: 5, name: "pig"},
]; 
let removeValFromIndex = [
    {id: 2, name: "cat"}, 
    {id: 5, name: "pig"},
]; 
_.forEach(removeValFromIndex, (indi) => {
    _.remove(valuesArr, (item) => {
        return item.id === indi.id;
    });
})

console.log(valuesArr)
/*[
    {id: 1, name: "dog"},  
    {id: 3, name: "rat"}, 
    {id: 4, name: "bat"},
]; */

Don't forget to clone (_.clone(valuesArr) or [...valuesArr]) before mutate your array