如何计算和求和数组每一列中的出现次数？

Question

I want to try to calculate the total occurrences for each "column of digits" in the following list of numbers.

8353
1619
6889
3850
7596
9594
2557
8838
6224
7075

My expected result for the first digits is:

array (
    8 => 2,  // 1st and 8th number starts with 8
    1 => 1,  // 2nd number
    6 => 2,  // 3rd and 9th
    3 => 1,  // 4th
    7 => 2,  // 5th and 10th
    9 => 1,  // 6th
    2 => 1,  // 7th
)

I need the same kind of calculation for the other columns (2nd digits, 3rd digits, 4th digits) all collected into a multi-dimensional array.

What I did so far was like this

while($rowny = mysqli_fetch_assoc($mulai)) {
    $rowData[] = $rowny;
}
for($i=0; $i<100; $i++){
    $hasil[] = $rowData[$i]['result'];

    $pecah = str_split($hasil[$i],1);
    $hitunga = array_count_values($pecah);

    print_r($hitunga);echo "<br/>";
}

So far when I print the $hitunga , it shows the array like this

Array ( [8] => 1 [3] => 2 [5] => 1 )
Array ( [1] => 2 [6] => 1 [9] => 1 )
Array ( [6] => 1 [8] => 2 [9] => 1 )
Array ( [3] => 1 [8] => 1 [5] => 1 [0] => 1 )
Array ( [7] => 1 [5] => 1 [9] => 1 [6] => 1 )
Array ( [9] => 2 [5] => 1 [4] => 1 )
Array ( [2] => 1 [5] => 2 [7] => 1 )
Array ( [8] => 3 [3] => 1 )
Array ( [6] => 1 [2] => 2 [4] => 1 )
Array ( [7] => 2 [0] => 1 [5] => 1 )

but this is changing the order of the digits and in some cases there are no numbers in the latter columns. I expect to maintain 4 columns of numbers and get the total occurrences in each column.

Answer 1

1. Split each number into a 4-element array.
   ( array_map('str_split', $numbers) )
2. Transpose the new multi-dimensional structure, IOW -- convert columns to rows.
   ( array_map(null, ...#1) )
3. Count the values.
   ( array_map('array_count_values', #2)

One-liner:

array_map('array_count_values', array_map(null, ...array_map('str_split', $numbers)))

Code: ( Demo )

var_export(
    array_map(
        'array_count_values',
        array_map(
            null,
            ...array_map(
                'str_split',
                $numbers
            )
        )
    )
);

---

Or if you prefer language constructs, this might be easier to comprehend...

Code: ( Demo )

$result = [];
foreach ($numbers as $number) {
    foreach (str_split($number) as $index => $digit) {
        $result[$index][$digit] = ($result[$index][$digit] ?? 0) + 1;
    }
}
var_export($result);

Output (from both snippets):

array (
  0 => 
  array (
    8 => 2,
    1 => 1,
    6 => 2,
    3 => 1,
    7 => 2,
    9 => 1,
    2 => 1,
  ),
  1 => 
  array (
    3 => 1,
    6 => 1,
    8 => 3,
    5 => 3,
    2 => 1,
    0 => 1,
  ),
  2 => 
  array (
    5 => 3,
    1 => 1,
    8 => 1,
    9 => 2,
    3 => 1,
    2 => 1,
    7 => 1,
  ),
  3 => 
  array (
    3 => 1,
    9 => 2,
    0 => 1,
    6 => 1,
    4 => 2,
    7 => 1,
    8 => 1,
    5 => 1,
  ),
)

Answer 2

Significantly less elegant and sophisticated, but this might be logic you're looking for?

<?php
$arr = [
    8353, 1619, 6889,3850, 7596, 9594, 2557, 8838, 6224, 7075,
];

foreach ($arr as $key => $val) {
    $split = str_split($val);
    $count[] = array_count_values($split);
}

foreach ($count as $key => $value) {
    $cleanCount[] = array_values($value);
}

// careful - numbers in table must be equal length
for ($i = 0; $i < strlen($arr[0]); $i++) {
    $result[$i] = array_sum(array_column($cleanCount, $i));
}

echo '<pre>';
print_r($result);
echo '</pre>';

Output (sum of count for each column):

Array
(
    [0] => 15
    [1] => 14
    [2] => 9
    [3] => 2
)

working demo