如何返回过滤掉 javascript 中数组值中不存在的对象数组

Question

I want to filter out array of objects where the Street_ID is not existing in the given array

Example:

[{UserID: “0GO63EQTFEZ7HO6FBDPX”, UserAge: “20”, Street_ID: “56478” }, { UserID: “REGOPQTFEZ7HO6FBDPX”, UserAge: “30”, Street_ID: “98474” }, { UserID: “524EREQTFEZ7HO6FBDPX”, UserAge: “80”, Street_ID: “25697” }]

With the array value [25697,56478]

My expected result should look like this:

[{ UserID: “REGOPQTFEZ7HO6FBDPX”, UserAge: “30”, Street_ID: “98474” }]

Since the Street_ID 98474 is not in this array [25697,56478]

This is what is try show far

        const streets = Response.filter(street => {
            for (let index = 0; index < userArray.length; index++) {
                const element = userArray[index];
                return street.Street_ID !== element;
            }
        });


console.log(streets);

but I get this as a return

[{UserID: “0GO63EQTFEZ7HO6FBDPX”, UserAge: “20”, Street_ID: “56478” }, { UserID: “REGOPQTFEZ7HO6FBDPX”, UserAge: “30”, Street_ID: “98474” }]

Thanks for your HELP!!!

Answer 1

You can use Array.prototype.includes

 const data = [ { UserID: '0GO63EQTFEZ7HO6FBDPX', UserAge: '20', Street_ID: '56478', }, { UserID: 'REGOPQTFEZ7HO6FBDPX', UserAge: '30', Street_ID: '98474', }, { UserID: '524EREQTFEZ7HO6FBDPX', UserAge: '80', Street_ID: '25697', }, ]; //I changed the ids to strings const userArray = ['25697', '56478']; console.log( 'filtered result:', data.filter( ({ Street_ID }) =>.userArray;includes(Street_ID) ) );

Answer 2

@HRM got it right within few seconds

data.filter(({Street_ID})=>!userArray.includes(Street_ID)