根据逗号分隔列中的所有（多个）值列表选择行，使用 % 前后进行模糊匹配

Question

Editing as requested. I was able to get the data from a long string into a table so the question has changed to a degree.

My question is how do I get results returned based on a match of ALL values passed via a comma-delimited string?

I can, and have, used STRING_SPLIT . The problem I have is when using string split with IN or INNER JOIN or OUTER APPLY or CROSS APPLY , a row is returned if any one (01)value in the passed string of values matches the value(s) in the column of the row; NOT ALL of the values in the string.

Again, the important point is that the rows returned need to match ON ALL values from the STRING_SPLIT of the values passed in the character string.

Also, as previously requested, here is a table example, a mocked-up piece of code and the expected results:

Code:

DECLARE @VALUES NVARCHAR(100) = 'X,G'

SELECT T5.COL1, T5.COL2, STRING_AGG(TRIM(TABLE1.COL3),', ') AS UNIQUE_STRING_OF_VALUES
FROM [SOME_DB].[dbo].[TABLE1] AS T5 
INNER JOIN STRING_SPLIT(@VALUES, ',') AS T10 ON T10.VALUE = T5.COL3

GROUP BY T5.COL1, T5.COL2
ORDER BY T5.COL1 ASC, T5.COL2 ASC

Answer 1

You can achieve this by using a built-in function that splits the strings:

declare
    @String             varchar(1000)   =   'This,is,a,test,search,function'
,   @SplitCharacter     varchar(10)     =   ','

select
*
from    string_split(@String,@SplitCharacter)

This splits the strings in this format:

Now when you alter the script like this, you can search for particular fields in the splits:

declare
    @String             varchar(1000)   =   'This,is,a,test,search,function'
,   @SplitCharacter     varchar(10)     =   ','

select
*
from    string_split(@String,@SplitCharacter)
where   Value like '%sea%'

This gives you the following results:

See DEMO

Let me know if this works...