Seaborn X 和 Y 散点图颜色

Question

I am having trouble coloring what should be a simple scatter plot. I am plotting two comparing columns in my pandas data frame, but I would like to color the scatter plot by X scatter and by Y scatter. So X scatter would be red and Y scatter will be black.

Here is a snippet of what I have done so far. This is with sns.lmplot, but I have tried with sns.scatterplot also.

fig, ax = plt.subplots(figsize=(10, 5))

x=df_layer10s2['xco2'].values
y=df_layer10s2['xco2_part'].values
col = (if x then 'r', else 'black')
ax= sns.lmplot(x='xco2',y='xco2_part',data=df_layer10s2)
# plt.ylim(389,404)
# plt.xlim(389,404)

also here is a image of how my dataframe is set up:

Answer 1

I think you are confusing the parameters of lmplot . Also, you could use regplot instead, as your not using the features that make lmplot different from regplot . Regardless, it seems you should be using your 'time' column as your x-values and 'xco2' and 'xco2_part' as y-values. In this case, you can make two plotting calls and set your color parameter. So something like this:

sns.regplot(x='time', y='xco2', data=df_layer10s2, color='r')
sns.regplot(x='time', y='xco2_part', data=df_layer10s2, color='k')

Here's an example:

np.random.seed(42)
time = np.random.random(50)
y0 = np.random.random(50)
y1 = np.random.random(50)
df = pd.DataFrame({'time': time, 'y0': y0, 'y1': y1})

sns.regplot(x='time', y='y0', data=df, color='r')
sns.regplot(x='time', y='y1', data=df, color='k')