MYSQL SELECT 查询中的 IF 语句

Question

I'm trying to add condition if user input language matches url language

SELECT DISTINCT *, IF(url_lang = 'en', weight = (weight+1.1)<10, weight = (weight-1.1)<10) as user_language_weight
                      FROM links                
                      WHERE (status='active'
                            AND type='url' 
                            AND MATCH(title,description,keywords) AGAINST('($op_word_1*) | ($op_word_2*) | ($op_word_3*) | ($op_word_4*) | ($op_word_5*) | ($acc_op_word_1) | ($acc_op_word_2) | ($acc_op_word_3) | ($acc_op_word_4) | ($acc_op_word_5)' IN BOOLEAN MODE)
                      GROUP BY host
                      ORDER BY weight DESC

According to the above, if statement is not working, I'm missing some logic here. Anyone care to correct or explain?

Answer 1

Thank you all for comments. Got the IF statement working, ex:

SELECT *, IF(url_lang = 'en', weight +1.1, weight -1.1) AS weight 
                  FROM links                
                  WHERE (status='active'
                        AND type='url' 
                        AND MATCH(title,description,keywords) AGAINST('($op_word_1*) | ($op_word_2*) | ($op_word_3*) | ($op_word_4*) | ($op_word_5*) | ($acc_op_word_1) | ($acc_op_word_2) | ($acc_op_word_3) | ($acc_op_word_4) | ($acc_op_word_5)' IN BOOLEAN MODE)
                  GROUP BY host
                  ORDER BY weight DESC