[英]How do I print x amount of integers per line in C?
How to print the integers
from 1 to 20 using a while loop and the counter
variable x
.如何使用 while 循环和counter
变量x
打印从 1 到 20 的integers
。
I need to print only five integers per line.我只需要每行打印五个整数。 [ Hint : Use the calculation x % 5
. [提示:使用x % 5
的计算。 When the value of this is 0
, print a newline character ( \n
), otherwise print a tab character ( \t
)]当 this 的值为0
时,打印一个换行符( \n
),否则打印一个制表符( \t
)]
My main question is: How to print 5 integers per line?我的主要问题是:如何每行打印 5 个整数?
This is the code i have tried这是我尝试过的代码
#include<stdio.h>
int main ( void )
{
int x = 0;
while ( x <= 20 )
{
printf("%d", x);
++x;
}
}
Print the integers from 1 to 20 using a while loop and the counter variable x.使用 while 循环和计数器变量 x 打印从 1 到 20 的整数。
but your code print the integers from 0 to 20, replace int x = 0;
但是您的代码打印从0到 20 的整数,替换int x = 0;
by int x = 1;
通过int x = 1;
Use the calculation
x % 5
.使用计算x % 5
。 When the value of this is 0, print a newline character, otherwise print a tab character.当 this 的值为 0 时,打印一个换行符,否则打印一个制表符。
in C that directly means在 C 中直接表示
putchar((x%5) ? '\t' : '\n');
or doing in the printf
或在printf
中做
printf("%d%c", x, (x%5) ? '\t' : '\n');
so finally your code can be:所以最后你的代码可以是:
#include<stdio.h>
int main (void)
{
int x = 1;
while ( x <= 20 ) {
printf("%d%c", x, (x%5) ? '\t' : '\n');
++x;
}
}
Compilation and execution:编译和执行:
pi@raspberrypi:/tmp $ gcc -Wall c.c
pi@raspberrypi:/tmp $ ./a.out
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
pi@raspberrypi:/tmp $
% is the modulo operation. % 是模运算。 a % b integer divide a by b and return the remainder. a % b integer a 除以 b 并返回余数。 Thus 3 % 5 -> 3 and 7 % 5 -> 2.因此 3 % 5 -> 3 和 7 % 5 -> 2。
You have the variable x which should go from 0 to 19. If you divide x by 5, the reminder will be a number in the range 0 to 4.您有变量 x,它应该 go 从 0 到 19。如果将 x 除以 5,则提示将是 0 到 4 范围内的数字。
For x = 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ..., x % 5 = 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 0, 1,...对于 x = 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ..., x % 5 = 0, 1, 2, 3, 4, 0, 1, 2 , 3, 4, 0, 1,...
As you can see, the remainder repeats the numbers from 0 to 4. These are 5 numbers.如您所见,余数重复从 0 到 4 的数字。这些是 5 个数字。
So the trick is to print a new line only when x % 5 equals 4.所以诀窍是仅当 x % 5 等于 4 时才打印新行。
int x = 0;
while (x < 20) {
printf("%d ", x+1);
if (x % 5 == 4)
printf("\n");
x++;
}
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