如果 function 在当前单词处被阻塞或花费太长时间，请跳到下一个单词

Question

I want for my function to skip to the next word if the execution either doesn't work or take too long. Here's my function:

def encode(word):
      return bc.encode([[word]],is_tokenized=True)

I tried the try/exepct like this:

def bert(word):
        try:
            return bc.encode([[word]],is_tokenized=True)
        except:
         pass

But my code still stop running for some words. Is there a function that can say to my function to pass to the next word if it takes too long?

Answer 1

I don't know what bc.encode is, but I googled it and if it's BertClient , according to this you can pass timeout=x to the constructor and I assume it will throw an exception if it takes more than that.