如何列出目录中的所有目录

Question

I would like to know if there's a quick 1 line of code to list all the directories in a directory. It's similar to this question: How do I list all files of a directory? , but with folders instead of files.

Answer 1

Here is a recipe for just the first level:

dname = '/tmp'
[os.path.join(dname, d) for d in next(os.walk(dname))[1]]

and a recursive one:

dname = '/tmp'
[os.path.join(root, d) for root, dirs, _ in os.walk(dname) for d in dirs]

(after import os , obviously)

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Note that on filesystems that support symbolic links, any links to directories will not be included here, only actual directories.

Answer 2

Using os.listdir to list all the files and folders and os.path.isdir as the condition:

import os   
cpath = r'C:\Program Files (x86)'
onlyfolders = [f for f in os.listdir(cpath) if os.path.isdir(os.path.join(cpath, f))]

Answer 3

Import os

#use os.walk()

Example:

For folder, sub, file in os.walk(path): Print(folder). #returns parent folder Print (sub). #returns sub_folder Print (file) # returns files

Answer 4

[ i[0] for i in os.walk('/tmp')]

1. here '/tmp' is the directory path for which all directories are listed
2. you need to import os

This works because i[0] gives all the root paths as it will walk through them so we don't need to do join or anything.