[英]Compute a field in Mongo DB
Hey Guys here is a document in my collection.嘿,伙计们,这是我收藏中的一份文件。 { Player_Name: Sandeep Nair Player_TotalWeightedPoints: 80 Player_Rank: 23 }
{ Player_Name: Sandeep Nair Player_TotalWeightedPoints: 80 Player_Rank: 23 }
There are close to 200 such documents.此类文件有近 200 份。 The Player_Rank field is a function of the total Weighted points, sorted in descending order.
Player_Rank 字段是总加权点数的 function,按降序排列。 The player with the highest weighted points having rank 1 and so on.
权重最高的玩家排名第一,依此类推。 I have 2 use cases
我有 2 个用例
How do I compute this Rank field in Mongo DB.如何在 Mongo DB 中计算此 Rank 字段。 ?
? Can someone throw some light please.
有人可以请放一些光。
Your question is not quite clear but i do have some suggestions for you.你的问题不是很清楚,但我确实有一些建议给你。
For case 1:对于案例 1:
it would be better if you assign some id with each player in order to get its other relevant details associated with him.如果您为每个玩家分配一些 id 以获得与他相关的其他相关详细信息,那会更好。
for now, let's assume that Player A has logged in with uid:123, you can use现在,假设玩家 A 使用 uid:123 登录,您可以使用
var data = db.player.find({}, {uid:123});
var rank = data.Player_Rank;
the rank of the player will be stored in rank variable which can be used anywhere in page.玩家的排名将存储在排名变量中,可以在页面的任何地方使用。
For case 2:对于案例 2:
After the input of points is inserted, sort the list with respect to points.插入点的输入后,根据点对列表进行排序。
db.player.find().sort({Player_TotalWeightedPoints : -1})
now we have sorted the list, now we can assign player rank by using range from 1 to 200现在我们已经对列表进行了排序,现在我们可以使用从 1 到 200 的范围来分配玩家排名
db.players.aggregate([{
$project: {
"Player_Rank": { $range: [ 1, 200] }
}
}])
this is the best which i can advice by looking at your question.这是最好的,我可以通过查看您的问题来提供建议。
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