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如何获取列表中被推回的元素的地址,在恒定时间内,在 c++ stl 中?

[英]How to get the address of the element which is pushed back in the list, In constant time,in c++ stl?

list<int> l;
list<int>::iterator lastElement;
lastElement=l.end()
l.push_back(10);
cout<<"Address of the element 10 in the list is"<<&lastElement<<endl;

Is the above way the correct way to get the address of the last element of a list in constant time.上述方法是在恒定时间内获取列表最后一个元素的地址的正确方法吗? I know there are many other methods but I want a method that gives the address in constant time.我知道还有很多其他方法,但我想要一种在恒定时间内给出地址的方法。

How to get the address of the element which is pushed back in the list, In constant time,in c++ stl?如何获取列表中被推回的元素的地址,在恒定时间内,在 c++ stl 中?

After pushing the element, use std::list::back to get reference to the element.推送元素后,使用std::list::back获取对元素的引用。 Then use the operator & to get the address of the element (or use std::addressof if the operator is overloaded, which is unusual).然后使用运算符 & 获取元素的地址(如果运算符重载,则使用std::addressof ,这是不寻常的)。

Is the above way the correct way to get the address of the last element of a list以上方法是获取列表最后一个元素地址的正确方法吗

No. There are several problems:不,有几个问题:

  • std::list:end returns an iterator to the element past the end of the list; std::list:end将迭代器返回到列表末尾之后的元素; not an iterator to the last element.不是最后一个元素的迭代器。
  • You take the iterator before pushing an element into the list.在将元素推入列表之前获取迭代器。 The iterator cannot possibly be to an element that you later push to the list.迭代器不可能指向您稍后推送到列表的元素。
  • You apply operator & on the iterator.您在迭代器上应用运算符 & 。 The result is the address of the iterator;结果是迭代器的地址; not the address of the element that the iterator points to.不是迭代器指向的元素的地址。

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