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如何在不复制的情况下将一个向量移动到另一个向量

[英]How to move one vector into another vector without copying

I have a large vector<object> created inside a scope that I want to push into a vector residing outside that scope without copying it (since it is very large).我在 scope 内部创建了一个大vector<object> ,我想将其推入位于 scope 外部的向量而不复制它(因为它非常大)。 Is there a way i can push vector v into vvec without doing a copy as I am doing currently?有没有一种方法可以将向量 v 推入 vvec 而无需像我目前所做的那样进行复制?

std:vector<std::vector<object>> vvec;
{
    std::vector<object> v;
    v.emplace_back(object());
    vvec.push_back(v);
}

You could std::move it你可以std::move

std::vector<std::vector<object>> vvec;
{
    std::vector<object> v;
    v.emplace_back(object());
    vvec.push_back(std::move(v));
}

If I mock a class as the following如果我模拟 class 如下

struct object
{
    object() { std::cout << "default construct\n"; }
    object(object const&) { std::cout << "copy construct\n"; }
    object(object&&) { std::cout << "move construct\n"; }
};

then the above snippet of code now produces the output那么上面的代码片段现在会生成 output

default construct
move construct

therefore the inner copy was avoided by the move.因此,内部副本被移动避免了。

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