我如何在序列中有 3 位数字的数字列（Oracle）中找到所有记录

Question

How would I find all records in a number column (Oracle) which have 3 digits in Sequence. Would I have to use substr to break down the number to individual digits and then subtract first and second digit to see if they are 1 or -1? Is there a better way to do it? Could I break down the number into digits and pass them to a varray in a pl/sql block? Please help.

Answer 1

Assuming that you mean "sequential" as in 1-2-3, then you can use brute force:

(case when regexp_like(ssn, '012|123|234|345|456|567|678|789')
      then 'in sequence' else 'not in sequence'
 end)