Python 中带有前瞻的正则表达式不匹配

Question

I have composed a regex pattern aiming to capture one date and one number from a sentence. But it does not.

My code is:

txt = 'Την 02/12/2013 καταχωρήθηκε στο Γενικό Εμπορικό Μητρώο της Υπηρεσίας Γ.Ε.ΜΗ. του Επιμελητηρίου Βοιωτίας, με κωδικόαριθμό καταχώρισης Κ.Α.Κ.: 110035'

p = re.compile(r'''Την\s? # matches Την with a possible space afterwards

               (?P<KEK_date>\d{2}/\d{2}/\d{4}) #matches a date of the given format and captures it with a named group
               
               \.+ # Allow for an arbitrary sequence of characters 
               
               (?=(κωδικ.\s?αριθμ.\s?καταχ.ριση.)|(κ\.?α\.?κ\.?:?\s*)) # defines two lookaheads, either of which suffices
               
               (?P<KEK_number>\d+) # captures a sequence of numbers''', re.I|re.VERBOSE)

p.findall(txt)

I would expect to return a list with two elements: '02/12/2013' and '110035' , but instead, it returns an empty list.

Answer 1

Issues:

• \.+ matches one or more dots, you need to use .+ (no escaping)
• (?=(κωδικ.\s?αριθμ.\s?καταχ.ριση.)|(κ\.?α\.?κ\.?:?\s*))(?P<KEK_number>\d+) will always prevent any match since the positive lookahead requires some text that is not 1 or more digits. You need to convert the lookahead to a consuming pattern.

I suggest fixing your pattern as

p = re.compile(r'''Την\s? # matches Την with a possible space afterwards
(?P<KEK_date>\d{2}/\d{2}/\d{4}) #matches a date of the given format and captures it with a named group
.+ # Allow for an arbitrary sequence of characters 
(?:κωδικ.\s?αριθμ.\s?καταχ.ριση.|κ\.?α\.κ\.:?)\s+ # defines two lookaheads, either of which suffices
(?P<KEK_number>\d+) # captures a sequence of numbers''', re.I | re.X)

See the regex demo

Details

• Την\s? - Την string and an optional whitespace
• (?P<KEK_date>\d{2}/\d{2}/\d{4}) - Group "KEK_date": a date pattern, 2 digits, / , 2 digits, / and 4 digits
• .+ - 1 or more chars other than line break chars as many as possible
• (?:κωδικ.\s?αριθμ.\s?καταχ.ριση.|κ\.?α\.κ\.:?) - either of
  • κωδικ.\s?αριθμ.\s?καταχ.ριση. - κωδικ , any char, an optional whitespace, αριθμ , any one char, an optional whitespace, καταχ , any 1 char, ριση and any 1 char (but line break char)
  • | - or
  • κ\.?α\.κ\.:? - κ , an optional . , α , an optional . , κ a . and then an optional :
• \s+ - 1+ whitespaces
• (?P<KEK_number>\d+) - Group "KEK_number": 1+ digits

See a Python demo :

import re
txt = 'Την 02/12/2013 καταχωρήθηκε στο Γενικό Εμπορικό Μητρώο της Υπηρεσίας Γ.Ε.ΜΗ. του Επιμελητηρίου Βοιωτίας, με κωδικόαριθμό καταχώρισης Κ.Α.Κ.: 110035'
p = re.compile(r'''Την\s? # matches Την with a possible space afterwards
(?P<KEK_date>\d{2}/\d{2}/\d{4}) #matches a date of the given format and captures it with a named group
.+ # Allow for an arbitrary sequence of characters 
(?:κωδικ.\s?αριθμ.\s?καταχ.ριση.|κ\.?α\.κ\.:?)\s+ # defines two lookaheads, either of which suffices
(?P<KEK_number>\d+) # captures a sequence of numbers''', re.I | re.X)
print(p.findall(txt)) # => [('02/12/2013', '110035')]