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在 Axios 中发出多个 Post 请求,然后获取所有响应以发出另一个请求

[英]Make Multiple Post Requests In Axios then get all the response to make another request

i have already make 2 request.., but i want to make a patch request using the id from each response...我已经提出了 2 个请求..,但我想使用每个响应中的 id 发出补丁请求...

the other one will be put in the first one and the second one will be in the data另一个将放在第一个中,第二个将放在数据中

can we maybe pass it to the var?我们可以将它传递给var吗? idk how to do that..我知道该怎么做..

for reference i use gatsbyjs and i use directusCMS供参考,我使用 gatsbyjs,我使用 directusCMS

let url3 = `${process.env.GATSBY_DIRECTUS_API_URL}/gemaclc/items/pendaftar/:id (the id should be from the first response that we just made)?access_token=${process.env.GATSBY_DIRECTUS_TOKEN}`;

axios.patch(url3, data, {
    
    data: JSON.stringify(
    {
        featured_image: 1 (id of the second response whcih is an image),
        
    
    }), 
})

event.preventDefault();

const data = new FormData() 
data.append('file', this.state.selectedFile)
console.warn(this.state.selectedFile);
console.log(data);

// console.log("User Email :"  + this.state.email)
// console.log("User nama :"  + this.state.name)
// console.log("User telepon :"  + this.state.telepon)
// console.log("User program :"  + JSON.stringify([this.state.program]))
// console.log("User tanggal :"  + this.state.tanggal_lahir)
// console.log("User tempat :"  + this.state.tempat_lahir)

let url = `${process.env.GATSBY_DIRECTUS_API_URL}/gemaclc/items/pendaftar?access_token=${process.env.GATSBY_DIRECTUS_TOKEN}`;

let url2 = `${process.env.GATSBY_DIRECTUS_API_URL}/gemaclc/files?access_token=${process.env.GATSBY_DIRECTUS_TOKEN}`;


let url2 = `${process.env.GATSBY_DIRECTUS_API_URL}/gemaclc/files?access_token=${process.env.GATSBY_DIRECTUS_TOKEN}`;

axios(url, {
    method: 'POST',
    headers: {
      'Accept': 'application/json',
      'Content-Type': 'application/json',
    },
    data: JSON.stringify({
      status:"published",
      nama: this.state.name,
      // email: this.state.email,
      // telepon: this.state.telepon,
      // program: [1],
      // tanggal_lahir: this.state.tanggal_lahir,
      // tempat_lahir: this.state.tempat_lahir,
    })
})
.then(res => {
  console.log(res)
  return axios.post(url2, data, {
    
    data: JSON.stringify(
    {
        data: data,
        
    
    }), 
})
})
.then(res => {
  console.log(res.data.data.id) 
  return axios.patch( url3, {

  })
})
.catch(error => {
    console.log(error)
});

I made a very simplified example of what you're trying to accomplish using async/await syntax since.then() would be messier to read;我做了一个非常简化的示例,说明您尝试使用 async/await 语法来完成什么,因为.then() 阅读起来会更麻烦; basically you can store the result of each post request in a variable to use in your patch request.基本上,您可以将每个发布请求的结果存储在一个变量中,以便在您的补丁请求中使用。 I'm not sure what your response object looks like, so you may have to do some additional property extraction.我不确定您的响应 object 是什么样的,因此您可能需要进行一些额外的属性提取。

//simulates 1st post request
const post1= new Promise((resolve, reject) => {
    setTimeout(() => resolve(1), 1000)
});

//simulates 2nd post request
const post2= new Promise((resolve, reject) => {
    setTimeout(() => resolve(2), 1000)
});

const groupedRequests = async() => {

    //represents calling your 1st post request;
    let id1 = await post1; 
    //represents calling your 2nd post request
    let id2 = await post2; 
  
    //represents your patch request
    console.log(id1, id2)
}
  
groupedRequests();

Edit: I went ahead and did the.then() version so you could see the comparison.编辑:我继续做了 .then() 版本,所以你可以看到比较。

//simulates 1st post request
const post1= new Promise((resolve, reject) => {
    setTimeout(() => resolve(1), 1000)
});

//simulates 2nd post request
const post2= new Promise((resolve, reject) => {
    setTimeout(() => resolve(2), 1000)
});

//stores first result
let id1; 

//represents callings 1st post request
post1
.then(result => {
    id1 = result;
    //represents calling 2nd post request
    return post2;
}).then(result => {
    let id2 = result; 
    //represents your patch request
    console.log(id1, id2)
})

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