在 Swift 中打开带有自动填充号码的手机应用程序

Question

Is there a way to open the phone app using swift? all the answer I see was to use UIApplication.shared.open(urlNumber) like this . but it's not opening the phone app, instead, it will create a pop up and a cancel or call option.

This is my expected output

the code that I was using right now was

guard let number = URL(string: "tel://" + "+639123123123") else { return }
UIApplication.shared.open(number, options: [:], completionHandler: nil)

but like I said, it didn't open the phone app and the output of that code was this, which is not what I expect.

Android achieved it in here , how about the ios?

Answer 1

Its not possible to open direct phone app without dialogue. As Per Apple's documentation for openURL:

openURL

When a third party application invokes openURL: on a tel://, facetime://, or facetime-audio:// URL, iOS displays a prompt and requires user confirmation before dialing.

Answer 2

This worked perfectly for me, plus you don't have to add any additional action sheets or alerts. An action sheet automatically pops up.

@objc private func didTapCall() {
    let numberString = self.phoneText.text!
    guard let url = URL(string: "telprompt://\(numberString)") else { return }
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
}