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Laravel 如何在前端路由参数中传递 null 值

[英]Laravel how to pass null value in route parameter in front end

I have a form and I'm trying to pass null value into the $dev-id parameter but it doesnt work, instead ti will replace the dev id parameter with the $id as shown in my code at the bottom,我有一个表格,我正在尝试将 null 值传递给$dev-id参数,但它不起作用,而是 ti 将用$id替换 dev id 参数,如底部代码所示,

The reason i needed it to be null because I'm using this function for 2 different page but one of the page doesn't have $dev_id .我需要它的原因是 null 因为我将这个 function 用于 2 个不同的页面,但其中一个页面没有$dev_id any help is appreciated任何帮助表示赞赏

HTML: HTML:

<form method="post"
    action="{{ route('admin.developers.admins.edit.post',['admin' => $admin, 'dev_id' => null, 'id' => $id]) }}" autocomplete="off" novalidate>

web.php: web.php:

Route::post('developers/{dev_id?}/admins/{id}/edit', 'Admin\DeveloperAdminController@postEditDeveloperAdmin')->name('admin.developers.admins.edit.post')->where(['dev_id' => '[0-9]+', 'id' => '[0-9]+']);

You can pass those parametres in the form of hidden input and in controller use request to get those values Add these to yur form您可以以隐藏输入的形式传递这些参数,并在 controller 使用请求获取这些值将这些添加到您的表单

 <input type="hidden" value="anything" name="dev_id"> 
Instead you are using vue use `v-model` instead of name and value 

Now modify your form like this现在像这样修改您的表单

<form method="post"
    action="{{ route('admin.developers.admins.edit.post',['admin' => $admin,'id' => $id]) }}" autocomplete="off" novalidate>

Now you are access that using $request object in your logic and check if the value is null or not现在您可以在逻辑中使用$request object 访问它,并检查该值是否为 null

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