如何在 python 中准确获取字典第一行的元素

Question

name,AGATC,AATG,TATC
Alice,2,8,3
Bob,4,1,5
Charlie,3,2,5

I did this:

with open(sys.argv[1], "r") as csvfile:

reader = csv.DictReader(csvfile)
for row in reader:
    print(','.join(row))

and it printed:

name,AGATC,AATG,TATC

name,AGATC,AATG,TATC

name,AGATC,AATG,TATC

I need to get access to AGATC AATG TATC i mean i have job to do with seperetly AGATC, AATG, TATC

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sorry this is my first question here so i little confused what is what thank you for answer

Answer 1

You can convert this reader object to list. See into the below code

import csv

with open("sample.csv", "r") as csvfile: 
    reader = csv.DictReader(csvfile)
    print(list(reader))

Answer 2

Assuming that your OP is the contents of csv file, you just need:

reader.fieldnames

or maybe

reader.fieldnames[1:]

To be specific, you are looking for the first row in the csv file, which is usually the header row. When you access the data rows with the Dict reader, you will get the data, with the keys provided by the header row.

for x in reader:
     print (x)

Will show you the rows of data, as OrderedDicts:

OrderedDict([('name', 'Alice'), ('AGATC', '2'), ('AATG', '8'), ('TATC', '3')])
OrderedDict([('name', 'Bob'), ('AGATC', '4'), ('AATG', '1'), ('TATC', '5')])
OrderedDict([('name', 'Charlie'), ('AGATC', '3'), ('AATG', '2'), ('TATC', '5')])