如何在列表的子列表中查找项目的索引（python）

Question

ExampleList = [['Ck'], ['Kat'], ['Arcadiusz']]

ExampleListFull = [['CK', 21, 'Male'], ['Kat', 19, 'Female'], ['Arcadiusz', 30, 'Male']]
           

User = str(input())
User = User.capitalise()

if ([User] in ExampleList) == True:

From here we want to find the Index of "User", lets go with Kat, I know it's 1, 0,
However I want the program to be able to tell me for what ever name is entered, this way I than can print
(User + '\'s', 'age is', (ExampleListFull(variable) (variable)))

Answer 1

I would recommend you to use a dictionary as you data structure here but is you need a list you could try using the index method as follow:

ExampleList = [['Ck'], ['Kat'], ['Arcadiusz']]

x = ExampleList.index(['Ck'])

print(x)

Output:

0

This returns the position at the first occurrence of the specified value

Answer 2

ExampleList = [['Ck'], ['Kat'], ['Arcadiusz']]

ExampleListFull = [['CK', 21, 'Male'], ['Kat', 19, 'Female'], ['Arcadiusz', 30, 'Male']]

User = str(input()) 
User = User.capitalize()
for Index,string in enumerate(ExampleList):
  
  if User == ExampleList[Index][0]:

    print(User + 's', 'age is ' + str(ExampleListFull[Index][1])) 

Answer 3

ExampleListFull = [['CK', 21, 'Male'], ['Kat', 19, 'Female'], ['Arcadiusz', 30, 'Male']]
User = str(input())
User = User.capitalise()

Here, we create a dummy list with the values of all the names. This should print ['CK', 'Kat', 'Arcadiusz']

names = [value[0] for value in data]
print(names)

The one-line for-loop is the equivalent of doing:

names = []
for value in data:
    names.append(value[0])

Then we can print the result

print(names.index(name))
print("Age is", {data[names.index(name)][1]})

This can all be shortened to just a few lines of code like this:

data = [['CK', 21, 'Male'], ['Kat', 19, 'Female'], ['Arcadiusz', 30, 'Male']]

User = str(input())
User = User.capitalise()

age = data[[value[0] for value in data].index(name)][1]
# gender= data[[value[0] for value in data].index(name)][2]