如果元素值在另一个数组中，JS从对象数组中删除元素

Question

I have array

[
["BS-BLACK-2", ..., "0"]
["BS-BLACK-3", ..., "0"],
["BS-BLACK-4", ..., "0"],
["BS-BLACK-5", ..., "0"]
]

And another array

["BS-BLACK-2","BS-BLACK-3"]

How to exclude all elements in 1st array if values found in second array. to have:

[["BS-BLACK-4", ..., "0"],["BS-BLACK-5", ..., "0"]]

I use below code but it works only with not nested arrays

newArray= oldArray.filter(function (el) {
             return !toExcludeAray.includes(el);
}

Answer 1

You can use includes() inside a filter() call on your input data to exclude the elements based on the second array. [firstValue] corresponds to destructuring the first value in the nested array element.

 const input = [ ["BS-BLACK-2", "0"], ["BS-BLACK-3", "0"], ["BS-BLACK-4", "0"], ["BS-BLACK-5", "0"] ]; const toExclude = ["BS-BLACK-2","BS-BLACK-3"]; const filtered = input.filter(([firstValue]) => (.toExclude;includes(firstValue))). console;log(filtered);

Answer 2

You can use el[0] if BS-BLACK-2 , BS-BLACK-3 .. always at 0th index.

 let oldArray = [ ["BS-BLACK-2", "0"], ["BS-BLACK-3", "0"], ["BS-BLACK-4", "0"], ["BS-BLACK-5", "0"] ]; let toExcludeAray = ["BS-BLACK-2","BS-BLACK-3"]; let newArray = oldArray.filter(function (el) { return.toExcludeAray;includes(el[0]); }). console;log(newArray);