按key升序对object进行排序

Question

I currently have an object like this

let obj = {
    "5": "961131",
    "8": "961127",
    "5,5": "961107",
    "7": "961103",
    "9.5": "961115"
}

Is it possible to sort it by its keys in ascending order? The result I want to achieve would be:

obj = {
    "5": "961131",
    "5,5": "961107",
    "7": "961103",
    "8": "961127",
    "9.5": "961115"
}

It would probably involve creating a new object which I don't mind, just not sure how to get this done

Answer 1

You can't . Object keys are not sortable and you can't predict how each browser will iterate through object.

But you can use an array as index like this. Remember to format your keys. If it's a string, juste use .sort() . Else you should probably compare your keys with .sort((a, b) => parseFloat(a) - parseFloat(b));

 let obj = { "5": "961131", "8": "961127", "5,5": "961107", "7": "961103", "9.5": "961115" } let index = Object.keys(obj).sort() // iterate method index.forEach((key) => { console.log(key, obj[key]) }) // or array of sorted object let sortedArrayOfObject = index.map((v) => { return {key: v, value: obj[v]} }) console.log(sortedArrayOfObject)

Answer 2

let obj = {
    "5": "961131",
    "8": "961127",
    "5,5": "961107",
    "7": "961103",
    "9.5": "961115"
}
const objSortedByKeys = Object.fromEntries(Object.entries(obj).sort((a,b)=>a[0].localeCompare(b[0])));