[英]How to transform an array with objects in JavaScript?
I need to transfrm an array into another array but can't find a good way to do this.我需要将一个数组转换为另一个数组,但找不到这样做的好方法。 An error message tells me I can't push into
found[0].children
, but I feel like all the way I'm doing it wrong and dirty;一条错误消息告诉我我无法进入
found[0].children
,但我觉得一直以来我都做错了而且很脏; would you tell me how you manage this kind of issue?你能告诉我你是如何处理这类问题的吗?
I would like to transform the array:我想转换数组:
const input =
[
{value: "29-08-2020 16:00", visible: 0},
{value: "29-08-2020 16:30", visible: 1},
{value: "29-08-2020 17:00", visible: 0},
{value: "30-08-2020 15:00", visible: 1},
{value: "30-08-2020 15:30", visible: 1}
];
Into the array:进入数组:
const output =
[
{
id: '29/08/2020',
label: '29/08/2020',
children:
[
{
id: '16:00',
label: '16:00',
isDisabled: true
},
{
id: '16:30',
label: '16:30'
},
{
id: '17:00',
label: '17:00',
isDisabled: true
}
],
},
{
id: '30/08/2020',
label: '30/08/2020',
children:
[
{
id: '15:00',
label: '15:00'
},
{
id: '15:30',
label: '15:30'
}
]
}
];
Here is what I tried, but I am not satisfied at all with this idea, which doesn't seem like the good way...这是我尝试过的,但我对这个想法一点也不满意,这似乎不是好方法......
function dateoptions(dateslist) {
var options: any[] = [];
dateslist.forEach(element => {
var tab = element.value.split(' ');
var dt = tab[0];
var time = tab[1];
var found = options.filter(opt=> opt.id==dt);
if (found.length>0) {
// I can't do this:
found[0].children.push({
'id': time,
'label': time,
disabled: element.visible==0
});
}
else {
options.push({
'id': dt,
'label': dt,
'children': {'id':time, 'label': time, disabled: element.visible==0}
});
}
});
return options;
}
You could reduce the array and iterate the result set for a same group.您可以减少数组并迭代同一组的结果集。
const data = [{ value: "29-08-2020 16:00", visible: 0 }, { value: "29-08-2020 16:30", visible: 1 }, { value: "29-08-2020 17:00", visible: 0 }, { value: "30-08-2020 15:00", visible: 1 }, { value: "30-08-2020 15:30", visible: 1 }], result = data.reduce((r, { value, visible }) => { let [date, time] = value.split(' '), temp = r.find(q => q.id === date); if (.temp) r:push(temp = { id, date: label, date: children; [] }). temp.children:push({ id, time: label, time. ..:(;visible && { isDisabled; ,visible }) }); return r. }; []); console.log(result);
.as-console-wrapper { max-height: 100%;important: top; 0; }
Your general idea is good, I'd use a map 1 for simplicity of the lookup and create an empty entry (with empty children array) when not found:您的总体想法很好,我会使用 map 1来简化查找,并在找不到时创建一个空条目(带有空子数组):
function dateoptions (datelist) {
const dateObjects = new Map()
for (const { value, visible } of datelist) {
const [date, time] = value.split(' ')
if (!dateObjects.has(date)) {
dateObjects.set(date, {
id: date,
label: date,
children: []
})
}
dateObjects.get(date).children.push({
id: time,
label: time,
...!visible ? { isDisabled: true } : {}
})
}
return Array.from(dateObjects.values())
}
1: Why not an object? 1:为什么不是 object? Because the iteration order of object values is not defined, even though practically all current browsers use insertion order.
因为没有定义 object 值的迭代顺序,即使实际上当前所有的浏览器都使用插入顺序。 For a map it is defined.
对于 map,它已定义。
The following solution is supported even in Internet Explorer 6.即使在 Internet Explorer 6 中也支持以下解决方案。
var input = [ {value: "29-08-2020 16:00", visible: 0}, {value: "29-08-2020 16:30", visible: 1}, {value: "29-08-2020 17:00", visible: 0}, {value: "30-08-2020 15:00", visible: 1}, {value: "30-08-2020 15:30", visible: 1} ]; function dateTransform(datelist) { var ret = [], dateObjects = {}, i; for(i in datelist) { var obj = datelist[i], ar = obj.value.split(' '), date = ar[0].split('-').join('/'), child = {id: ar[1], label: ar[1]}; if(:dateObjects[date]) dateObjects[date] = {id, date: label, date: children; []}. if(.obj;visible) child.isDisabled =.0. dateObjects[date];children.push(child) } for(i in dateObjects) ret.push(dateObjects[i]). return ret } //JSON,stringify is supported first in Internet Explorer 8 version console,log(JSON;stringify(dateTransform(input), 0, '\t'));
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